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a_sh-v [17]
3 years ago
13

Mass is measured using _____.

Chemistry
2 answers:
oee [108]3 years ago
4 0
Kilograms? im assuming. bcz weight is like newtons or sum shii..
Luda [366]3 years ago
3 0
Kilograms hope this helps not sure if im correct
You might be interested in
Relative to protons, electrons have:
saw5 [17]

Answer:

<u><em>(B.) a significantly lower mass that protons</em></u>

Explanation:

The mass (in g) of an electron is 9.11 ×10^{-28}g, which is significantly lower than the mass of protons and neutrons which are approximately the same. They are extremely small (equal to 0 amu), contributing nothing to the overall mass of the atom.

The nucleus has a mass of 1 amu and is positively charged.

6 0
3 years ago
Abnormal behavior is defined as a?
hodyreva [135]

Answer:

Abnormality is a behavioral characteristic assigned to those with conditions regarded as rare or dysfunctional. Behavior is considered abnormal when it is atypical or out of the ordinary, consists of undesirable behavior, and results in impairment in the individual's functioning

Explanation:

5 0
2 years ago
a scientist uses 68 grams of CaCo3 to prepare 1.5 liters of solution. what is the molarity of this solution?
victus00 [196]

Answer: 0.4533mol/L

Explanation:

Molar Mass of CaCO3 = 40+12+(16x3) = 40+12+48 = 100g/mol

68g of CaCO3 dissolves in 1.5L of solution.

Xg of CaCO3 will dissolve in 1L i.e

Xg of CaCO3 = 68/1.5 = 45.33g/L

Molarity = Mass conc.(g/L) / molar Mass

Molarity = 45.33/100 = 0.4533mol/L

7 0
3 years ago
A snowflake contains 2.1 10^18 molecules of water. How many moles of water does it contain?
IgorC [24]

Answer:

divide the # of molecules by avogadros number and get 3.48 x 10^-6

Explanation:

6 0
2 years ago
4. When 1.00 L of 1.00 M Ba(NO3)2 solution at 25.0˚C is mixed with 1.00 L of 1.00 M Na2SO4 solution at 25.0˚C in a calorimeter,
myrzilka [38]

Answer:

The final temperature of the mixture is 28.11 °C

Explanation:

Step 1: Data given

Volume of 1.00 M Ba(NO3)2 = 1.00 L

Temperature = 25.0 °C

Volume of 1.00 M Na2SO4 = 1.00 L

enthalpy change is – 26 kJ per mol BaSO4

The specific heat of water is 4.18 J/g ·˚C

the density of water is 1.00 g/mL

Step 2: The balanced equation

Ba(NO3)2(aq) + Na2SO4(aq) → 2NaNO3(aq) + BaSO4(s)

Step 3: Calculate the total volume

Total volume = 1.00 L + 1.00 L = 2.00 L = 2000 mL

Step 4: Calculate mass

Mass = volume * density

Mass = 2000 mL * 1g/mL

Mass = 2000 grams

Step 5: Calculate moles BaSO4 formed

For 1 mol Ba(NO3)2 we need 1 mol Na2SO4 to produce 1 mol BaSO4

There is no limiting reactant, both Ba(NO3)2 and Na2SO4 will be completely be consumed (1 mol). We'll have 1.0 mol of BaSO4 produced.

Step 6: Calculate Q

Q = - ΔH

ΔH is negative so the reaction is exothermic, what means the temperature increases

Q is always positive, so Q = 26kJ = 26000 J

Step 6: Calculate the heat transfer

Q= m*c*ΔT

⇒with Q = the heat transfer = TO BE DETERMINED

⇒with m =the mass of the solution = 2000 grams

⇒with c= the specific heat of the solution = 4.18 J/g°C

⇒with ΔT = the change of temperature = T2 - T1 = T2 - 25.0

26000 = 2000 * 4.18 * (T2 - 25.0 °C)

3.11 = T2 - 25.0 °C

T2 = 25.0 + 3.11 °C

T2 = 28.11 °C

The final temperature of the mixture is 28.11 °C

7 0
3 years ago
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