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iren [92.7K]
3 years ago
5

The nearest known exoplanets (planets beyond the solar system) are around 20 light-years away. What would have to be the minimum

diameter of an optical telescope to resolve a Jupiter-sized planet at that distance using light of wavelength 600 nm? (Express your answer to two significant figures.)
Physics
1 answer:
dem82 [27]3 years ago
3 0

To solve the problem, it is necessary to apply the concepts related to the diffraction given in circular spaces. By definition it is expressed as

\Delta \theta = 1.22\frac{\lambda}{d}

Where,

\lambda = Wavelength

d = Optical Diameter

\theta = Angular resolution

In turn you can calculate the angle through the diameter and the arc length, that is,

\Delta \theta = \frac{x}{D}

Where,

x = The length of the arc

D = Distance

From known data we know that Jupiter's diameter is,

x_J = 1.43*10^8m

D = 20*9.4608*10^{15}

\lambda = 600*10^{-9}m

Replacing we have that,

\frac{x}{D} = 1.22\frac{\lambda}{d}

\frac{1.43*10^8}{20*9.4608*10^{15} } = 1.22\frac{600*10^{-9}}{d}

Re-arrange to find d,

d = 968.5m = 0.968Km

Therefore the minimum diameter of an optical telescope to resolve a Jupiter-sized planet is 0.968Km.

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mash [69]

Answer:

1/ 485.6 Nm

2/ Clock-wise

3/ 0 and no direction

4/ 1.62 m

Explanation:

1/ Torque is gravity force times the moment arm. Let's g = 9.81m/s2

T_2 = m_2*g*d_2 = 45*9.81*1.1 = 485.6 Nm

2/ If person 2 is sitting on the right, the direction of this torque is clock-wise, since the gravity is acting downward.

3/ Assuming that location A is right at the pivot point, then the torque generated by this torque is 0, since the moment arm is 0. This has no direction.

4/ The seasaw is balanced, this means torques generated by 2 people are equal and in opposite direction

T_1 = T_2

m_1gd_1 = m_2g_d_2

m_1d_1 = m_2d_2

d_2 = \frac{m_1d_1}{m_2} = \frac{91*0.8}{45} = 1.62m

So the new location for d2 is 1.62m

5 0
3 years ago
Modern wind turbines are larger than they appear, and despite their apparently lazy motion, the speed of the blades tips can be
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<span>The speeds of a modern turbine that has blades that are 56 m long averages around 40 mph. It varies by how much rpm's it uses at the given time. The lower the rpm's, the lower mph it will be. Likewise, the higher the rpm's, the higher mph is will be.</span>
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4 years ago
An electron and a proton are both released from rest, midway between the plates of a charged parallel-plate capacitor. The only
topjm [15]

Answer:

Explanation:

Let the potential difference between the middle point and one of the plate be ΔV .

electric potential energy will be lost and it will be converted into kinetic energy .

Electrical potential energy lost = Vq , where q is charge on charge particle .

For proton

ΔV× q = 1/2 M V² ( kinetic energy of proton )

where M is mass and V be final velocity of proton .

For electron

ΔV× q = 1/2 m v² ( kinetic energy of electron  )

where m is mass and v be final velocity of electron . Charges on proton and electron are same in magnitude .

As LHS of both the equation are same , RHS will also be same . That means the kinetic energy of both proton and electron will be same

1/2 M V² =  1/2 m v²

(V / v )² = ( m / M )

(V / v ) = √ ( m / M )

In other words , their velocities  are  inversely proportional to square root of their masses .

4 0
4 years ago
What is the relationship Between Voltage and Cerrent source with a theorem​
lora16 [44]

Answer:

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3 0
3 years ago
A 0.25 kg ball is rolled across the floor with a velocity of 3.5 m/s. What is the ball's momentum?
solniwko [45]
<h2>Answer:0.875Kgms^{-1}</h2>

Explanation:

Momentum is defined as the product of mass of an object and the velocity of that object.

Let m be the mass of the object.

Let v be the velocity of the object.

Let p be the momentum of the object.

Given that m=0.25Kg

v=3.5ms^{-1}

p=mv

p=0.25\times 3.5=0.875Kgms^{-1}

7 0
3 years ago
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