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2 years ago

Calculate the force of gravity on the same 1 kg mass if it were 6.4x10^6 m above earth's surface

1 answer:

3 0

The force of gravity on a certain object is calculated through the equation,

F = Gm1m2 / r²

where F is the force, G is a constant, m1 and m2 are masses of the object and Earth, respectively and r is the distance. Substituting the known values for this item,

F = (6.67 x 10⁻¹¹ N.m²/kg²)(1 kg)(5.98 x 10²⁴ kg)/ (6.4 x 10⁶ m)²

F = 9.37 N

Answer: 9.37 N

You might be interested in

Does the construction of a high building slow down the rotation of the earth

omeli [17]

No, the building's size in comparison to the earth would have no change or change so increadibly miniscule, like if you were told to spin slowly and an and was placed on top of your head

5 0

3 years ago

An electric pump rated at 1000W, takes 16 seconds to pump 100 kg of water out to a tank at a height of 10 m. what is the efficie

TEA [102]

Answer:

$\boxed{\sf Efficiency \ of \ the \ motor = 62.5 \ \%}$

Given:

Input Power ( $\sf P_i$ )= 1000 W

Mass (m) = 100 kg

Height (h) = 10 m

Time (t) = 16 s

To Find:

Efficiency of the motor

Explanation:

$\boxed{ \bold{Output \: power \: (P_o)= \frac{mgh}{t}}}$

$\sf \implies P_o = \frac{100 \times 10 \times 10}{16}$

$\sf \implies P_o = \frac{10000}{16}$

$\sf \implies P_o = \frac{ \cancel{16} \times 625}{ \cancel{16}}$

$\sf \implies P_o = 625 \: W$

$\boxed{ \bold{Efficiency = \frac{Output \ Power \ (P_o)}{Input \ Power \ (P_i) } \times 100}}$

$\sf \implies Efficiency = \frac{625}{10 \cancel{00}} \times \cancel{100}$

$\sf \implies Efficiency = \frac{625}{10}$

$\sf \implies Efficiency = 62.5 \: \%$

$\therefore$

Efficiency of the motor = 62.5 %

5 0

3 years ago

Someone pls answer this

andriy [413]

Answer:

The speed of metal block B is 5 m/s after the collision

Explanation:

Law Of Conservation Of Linear Momentum

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is

P=mv.

If we have a system of bodies, then the total momentum is the sum of them all

$P=m_1v_1+m_2v_2+...+m_nv_n$

If some collision occurs, the velocities change to v' and the final momentum is:

$P'=m_1v'_1+m_2v'_2+...+m_nv'_n$

In a system of two masses, we have:

$m_1v_1+m_2v_2=m_1v'_1+m_2v'_2$

The metal block A has a mass of m1=3.2 Kg and moves at v1=4 m/s. Metal block b has a mass of m2=1.6 Kg and is initially at rest v2=0.

After the collision occurs, block A moves at v1'=1.5 m/s. We need to calculate the speed of the metal block B. Solving for v2':

$\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}$

Substituting the given values:

$\displaystyle v'_2=\frac{3.2*4+1.6*0-3.2*1.5}{1.6}$

$\displaystyle v'_2=\frac{8}{1.6}$

$\displaystyle v'_2=5\ m/s$

The speed of metal block B is 5 m/s after the collision

8 0

2 years ago

How was the age of the Earth determined? (site 1)

Fudgin [204]

HEllO PAIGE❤️

The age of earth is determined truly by the RADIOCARBON MATHOD . In this method we can find the actuall age of anything having carbon .

Hope it helps you.

8 0

3 years ago

If a bale of hay behind the target exerts a constant friction force, how much farther will your arrow burry itself into the hay

LenaWriter [7]

Answer:

The arrow will bury itself farther by 3S₁

Explanation:

lets assume; the Arrow shot by me has a speed twice the speed of the arrow fired by the younger shooter

Given that ; acceleration is constant , Frictional force is constant

A₂ = A₁

Vf²₂ - Vi²₂ / 2s₂ = Vf₁² - Vi₁² / 2s₁ ---- ( 1 )

final velocities = 0

Initial velocities : Vi₂ = 2(Vi₁ )

Back to equation 1

0 - (2Vi₁ )² / 2s₂ = 0 - Vi₁² / 2s₁

hence :

s₂ = 4s₁

hence the Arrow shot by me will burry itself farther by :

s₂ - s₁ = 3s₁

Note : S1 = distance travelled by the arrow shot by the younger shooter

8 0

2 years ago