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swat32
3 years ago
11

Dean is conducting a science experiment. He wants to see how the average length of an earthworm changes with its age.

Chemistry
2 answers:
Volgvan3 years ago
7 0

Answer:

I would use centimeters.

Explanation:

garik1379 [7]3 years ago
6 0

Answer:

B.

centimeter

Explanation:

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Get correct for brainleist!
soldier1979 [14.2K]
I would say d
Hope that helps :)
5 0
3 years ago
Which element in group 2 (Alkaline Earth Metals) is the most reactive?
never [62]

Answer:

the reactivity of alkaline earth metals increases from top to the bottom of the group, that's because the atoms get bigger from the top to the bottom so the valence electrons are farther from the nucleus.

8 0
3 years ago
How many more grams should be added​
Minchanka [31]

Answer:

50?

I think but not 100% sure if not lmk

4 0
3 years ago
How many moles of carbon are in 7.00 x 1023 atoms of carbon?
Andru [333]

Answer:

<h2>1.16 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{7 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{7}{6.02}  \\  = 1.162790....

We have the final answer as

<h3>1.16 moles</h3>

Hope this helps you

8 0
3 years ago
What volume is occupied by 3.760 g of oxygen gas at a pressure of 88.4
Lorico [155]

Answer:

3.2 L

Explanation:

Given data:

Mass of oxygen = 3.760 g

Pressure of gas = 88.4 Kpa (88.4×1000 = 88400 Nm⁻²)

Temperature = 19°C (19+273.15 = 292.15 K)

R = 8.314 Nm K⁻¹ mol⁻¹

Volume occupied = ?

Solution:

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 3.760 g/ 32 g/mol

Number of moles = 0.12 mol

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant

T = temperature in kelvin

V = nRT/P

V = 0.12 mol ×  8.314 Nm K⁻¹ mol⁻¹ × 292.15 K /88400 Nm⁻²

V = 291.472 Nm /88400 Nm⁻²

V = 0.0032 m³

m³ to L:

V = 0.0032×1000 = 3.2 L

4 0
3 years ago
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