All categories

2 years ago

How many moles of nacl are required to make 500. 0 ml of a 0. 1 m solution of nacl?.

Chemistry

1 answer:

Illusion [34]2 years ago

7 0

Answer:

Therefore 500 ml of solution have 0.25 mol of NaCl .. = 14.61 g (ans.)

Explanation:

You might be interested in

Atoms of two different elements must have different

attashe74 [19]

Atomic number The atomic number of each element is different than other Elements.

8 0

3 years ago

Read 2 more answers

What is the correct electron configuration of the element with atomic number 20?

IgorLugansk [536]

Answer:

D is the correct answer

s orbital contain 2

p orbital contains 6

3 0

2 years ago

Please help me

klio [65]

Answer:

Vascular plants are successful due to better transportation for water, nutrients and reproduction.

Explanation:

I got it right at school and hope this helps you learn to STUDY.jk

6 0

3 years ago

Use the following equation to determine how many moles of C are needed to react with 0.500 mole of SO2.

Maru [420]

Answer:

The answer to your question is 1.25 moles of C

Explanation:

Reaction

5C + 2SO₂ ⇒ CS₂ + 4CO

Check that the reaction is balanced

Reactant Element Product

5 C 5

2 S 2

4 O 4

Use proportions to find the moles of C needed.

5 moles of C ----------------- 2 moles of SO₂

x moles of C ---------------- 0.500 moles of SO₂

x = (0.500 x 5) / 2

x = 1.25 moles of C

8 0

3 years ago

A compound, C4H6O, exhibits IR absorption at 1705 cm-1. Its carbon NMR shifts are given below. The number of hydrogens at each c

Airida [17]

Answer:

Methacrylaldehyde

Explanation:

The first step is the calculation of the IHD (index hydrogen deficiency):

$IHD=~\frac{2C+2+N-H-X}{2}$

$IHD=~\frac{2(2)+2-6}{2}=2$

This value indicates that we have 2 double bonds. Now, if we check the IR info we can conclude that we have an oxo group (C=O) due to the signal in 1705 cm^-1 . So, the options that we can have are aldehyde or ketone.

If we analyze the NMR info we have a signal in 194.7 with only 1 hydrogen. This indicates that necessary we have an aldehyde due to the hydrogen. Also, for the signal in 14 we will have a $CH_3$ , for the signal at 134.2 we will have a $CH_2$ and for the signal at 146.0 we will have a quaternary carbon (no hydrogens present).

So, we will have a $CH_3$ , $CH_2$ , C (without hydrogens), an aldehyde group and a double bond.

When we put all this together we will obtain the Methacrylaldehyde (see figure).

5 0

3 years ago