The number of particles= 1.43 x 10²⁴ particles
<h3>Further explanation</h3>
Given
53.2 L volume of gas at STP
Required
The number of particles
Solution
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.
So mol for 53.2 L :
= 53.2/22.4
= 2.375 moles
1 mol = 6.02 x 10²³ particles (molecules, atoms, ions)
The number of paricles for 2.375 moles gas :
= 2.375 x 6.02 x 10²³
= 1.43 x 10²⁴ particles
2.2Giga
Explanation:
Given that the number of years = 71years
We need to convert this to seconds;
60s = 1 min
60 min = 1hr
24hr = 1 day
7 days = 1 week
52 weeks = 1yr
71 years x
= 2,232,921,600s
This value is 2.2 x 10⁹s = 2.2Giga
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Answer:
The answer is D.
Explanation:
I know because I am currently doing this topic in Chemistry as well. I hope it was enough.