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zzz [600]
3 years ago
11

I have 2 samples of solid chalk (aka calcium carbonate). Sample A has a total mass of 4.12 g and Sample B has a total mass of 19

.37 g. What is the difference between the samples?
A) Sample B has more calcium carbonate molecules
B) Sample B has a larger ratio of carbon, oxygen, and calcium atoms
C) Sample B has more calcium ion than carbonate ions
D) Sample B must have some impurity
Chemistry
1 answer:
IRINA_888 [86]3 years ago
7 0

Answer:

A) Sample B has more calcium carbonate molecules

Explanation:

M = Molar mass of calcium carbonate = 100.0869 g/mol

N_A = Avogadro's number = 6.022\times 10^{23}\ \text{mol}^{-1}

For the 4.12 g sample

Moles of a substance is given by

n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{4.12}{100.0869}\\\Rightarrow n=0.0411\ \text{mol}

Number of molecules is given by

nN_A=0.0411\times 6.022\times 10^{23}=2.48\times 10^{22}\ \text{molecules}

For the 19.37 g sample

n=\dfrac{19.37}{100.0869}\\\Rightarrow n=0.193\ \text{mol}

Number of molecules is given by

nN_A=0.193\times 6.022\times 10^{23}=1.16\times 10^{23}\ \text{molecules}

1.16\times 10^{23}\ \text{molecules}>2.48\times 10^{22}\ \text{molecules}

So, sample B has more calcium carbonate molecules.

The ratio of the elements of carbon, oxygen, calcium atoms, ions, has to be same in both the samples otherwise the samples cannot be considered as calcium carbonate. Same is applicable for impurities. If there are impurites then the sample cannot be considered as calcium carbonate.

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3 years ago
What is the molarity of a solution that contains 148g NaOH in 4.00 L solution? a 0.925 M b 0.0253 M c 0.459 M d 1.363 M
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15 mL of a 0.16 M solution of glucose was diluted until the total volume reached 95 mL. What is the concentration of new solutio
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