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3 years ago

Which force is responsible for producing a stable

2 answers:

swat323 years ago

6 0

A strong force 's responsible for producing a stable nucleus by opposing the electrostatic force of repulsion between protons.

WARRIOR [948]3 years ago

5 0

Answer:

(1) Strong Nuclear Force

Explanation:

When protons are placed very close to each other in the space which is very small i.e. inside the nucleus then the force between them is known as Strong nuclear force.

This strong nuclear force only depends on the distance between the protons or protons and neutrons. As the distance is decreased to very small value then this force also changes to repulsion force.

While electrostatic force between the protons is very small or negligible as we compare it with nuclear force.

So here correct answer will be

(1) Strong Nuclear Force

You might be interested in

The human body obtains 915 kj of energy from a candy bar. if this energy were used to vaporize water at 100.0 °c, how much water

monitta

The volume of water vaporized by the energy from the candy bar is $\boxed{403.44\,{\text{ml}}}$ or $\boxed{0.403\,l}$ .

Further Explanation:

Given:

The amount of energy given by the candy bar is $915\,{\text{kJ}}$ .

The density of the water is $1.0\,{{\text{g}} \mathord{\left/ {\vphantom {{\text{g}} {{\text{ml}}}}} \right. \kern-\nulldelimiterspace} {{\text{ml}}}}$ .

Concept:

The amount of energy provided by the candy bar changes the state of the water and vaporizes it. The energy required for the evaporation is given by the formula.

$\boxed{Q = m{L_v}}$

Here, $Q$ is the energy given by candy bar, $m$ is the mass of the water evaporated and ${L_v}$ is the latent heat of vaporization.

Substitute $915\,{\text{kJ}}$ for $Q$ and $2268\,{{\text{J}} \mathord{\left/{\vphantom {{\text{J}} {\text{g}}}} \right.\kern-\nulldelimiterspace} {\text{g}}}$ for ${L_v}$ in above expression.

$\begin{aligned}9.15 \times {10^5} &= m \times 2268 \\m&= \frac{{9.15 \times {{10}^5}}}{{2268}}\,{\text{g}}\\&= {\text{403}}{\text{.44}}\,{\text{g}} \\\end{aligned}$

Convert the mass of the water into the volume.

$V = \dfrac{m}{\rho }$

Substitute $403.44\,{\text{g}}$ for $m$ and $1.0\,{{\text{g}} \mathord{\left/{\vphantom {{\text{g}} {{\text{ml}}}}} \right.\kern-\nulldelimiterspace} {{\text{ml}}}}$ for $\rho$ in above expression.

$\begin{aligned}V &= \frac{{403.44\,{\text{g}}}}{{1.0\,{{\text{g}} \mathord{\left/{\vphantom {{\text{g}} {{\text{ml}}}}} \right. \kern-\nulldelimiterspace} {{\text{ml}}}}}} \\&= 403.44\,{\text{ml}}\\\end{aligned}$

Thus, the volume of water vaporized by the energy from the candy bar is $\boxed{403.44\,{\text{ml}}}$ or $\boxed{0.403\,l}$ .

Learn More:

In the calorimetry experiment which energy will be calculated during the heat exchange if water is used brainly.com/question/2566525
One consequence of the third law of thermodynamics is that brainly.com/question/3564634
John and caroline go out for a walk one day. This graph represents their distance from home. Which statement accurately describes their walk brainly.com/question/11313502

Answer Details:

Grade: High School

Chapter: Heat Transfer

Subject: Physics

Keywords: Human body, energy, from a candy bar, latent heat of vaporization, volume of water, vaporized, evaporation, changes the state.

5 0

3 years ago

Read 2 more answers

it's nighttime, and you've dropped your goggles into a swimming pool that is 3.2 m deep. If you hold a laser pointer 1.0 m above

Scrat [10]

Answer:

5.2 m

Explanation:

from the question we are given the following

depth of pool (d) = 3.2 m

height of laser above the pool (h) = 1 m

point of entry of laser beam from edge of water (l) = 2.5 m

we first have to calculate the angle at which the laser beam enters the water (∝),

tan ∝ = \frac{1}{2.2}

∝ = 24.44 degrees

from the attached diagram, the angle with the normal (i) = 90 - 24.4 = 65.56 degrees

lets assume it is a red laser which has a refractive index of 1.331 in water, and with this we can find the angle of refraction (r) using the formula below

refractive index = \frac{sin i}{sin r}

1.331 = \frac{sin 65.56}{sin r}

r = 43.16 degrees

we can get the distance (x) from tan r = \frac{x}{3.2}

tan 43.16 = \frac{x}{3.2}

x = 3 m

To get the total distance we need to add the value of x to 2.2 m

total distance = 3 + 2.2 = 5.2 m

3 0

3 years ago

Can someone please put these vocab terms in the right boxes

umka2103 [35]

Conduction:

The handle of a pot becoming too hot to grab as it cooks on the stove.

Grabbing a warm coffee mug to warm your hands.

Putting an ice pack on an injury.

Burning yourself by touching boiling water.

Convection:

An oven that cooks by cycling warm air through the bottom and out the top.

Warm water rising to the surface of the ocean and cooler water sinking.

Cooking popcorn using a microwave.

Radiation:

Heat from a fire warming your hands.

Warm air rising off of the pavement.

Heat from the sun hitting a solar panel.

Hope this helps ☝️☝☝

7 0

4 years ago

A 25 kg child stands 2.5 m from the center of a frictionless merry‐go‐round, which has a 200 kg*m^2 moment of inertia and is spi

vodka [1.7K]

Answer:

Explanation:

a ) Time period T = 2 s

Angular velocity ω = 2π / T

= 2π / 2 = 3.14 rad /s

Initial moment of inertia I₁ = 200 + mr²

= 200 + 25 x 2.5²

=356.25

Final moment of inertia

I₂ = 200 + 25 X 1.5 X 1.5

= 256.25

b ) We apply law of conservation of momentum

I₁ X ω₁ = I₂ X ω₂

ω₂ = I₁ X ω₁ / I₂

Putting the values

$w_2=\frac{356.25\times3.14}{256.25}$

ω₂ = 4.365 rad s⁻¹

c ) Increase in rotational kinetic energy

=1/2 I₂ X ω₂² - 1/2 I₁ X ω₁²

.5 X 256.25 X 4.365² - .5 X 356.25 X 3.14²

= 684.95 J

This energy comes from work done against the centripetal pseudo -force.

7 0

3 years ago

A tourist stands at the top of the Grand Canyon, holding a rock, overlooking the valley below. Find the final velocity, and disp

uranmaximum [27]

Answer:

a. Vf = 39.24 [m/s]

b. Vf = 31.24 [m/s]

c. Vf = 47.24 [m/s].

Explanation:

To solve this problem we can use the following equation of kinematics. We have to keep in mind that the gravitational acceleration acts downwards, therefore when the rock falls towards the abyss it has the same direction of the acceleration and that is why the gravitational acceleration has a positive sign in the equation.

$v_{f}=v_{o}+g*t$

where:

Vf = final velocity [m/s]

Vo = initial velocity = 0 (when the rock is dropped)

g = gravitational acceleration = 9.81 [m/s²]

t = time = 4 [s]

$v_{f}=0+9.81*4\\v_{f}= 39.24 [m/s]$

In this particular situation, the acceleration will be taken as negative because the gravity is pointing in the opposite direction of the movement of the rock.

$v_{f}=8-(9.81*4)\\v_{f}=-31.24[m/s]$

The negative sign in the answer tells us that the rock no longer moves up instead it does downwards when 4 seconds have passed.

$v_{f}=8+(9.81*4)\\v_{f}=47.24[m/s]$

4 0

3 years ago