Answer:
-2x-2
For a line equation for the form of y = mx +b, the slope is m
m= -2
The function has no undefined points nor domain
constraints. There fore, the domain is
domain: -∞<x<∞
The range of polynomial with odd degrees is all the real numbers
range: -∞<f(x)<∞
Step-by-step explanation:
graph is inserted
Answer:
No mode
Step-by-step explanation:
The mode is the statistical method in which the most repetitive number should be considered
Like if we take an example
1,1, 2, 2, 2, 4, 4,4,4
So here the mode is 4 as 4 is repeated 4 times
But in the given situation there is no mode as every number is written single time
Answer:
∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c.
Step-by-step explanation:
In order to solve this question, it is important to notice that the derivative of the expression (1 + sin(x)) is present in the numerator, which is cos(x). This means that the question can be solved using the u-substitution method.
Let u = 1 + sin(x).
This means du/dx = cos(x). This implies dx = du/cos(x).
Substitute u = 1 + sin(x) and dx = du/cos(x) in the integral.
∫((cos(x)*dx)/(√(1+sin(x)))) = ∫((cos(x)*du)/(cos(x)*√(u))) = ∫((du)/(√(u)))
= ∫(u^(-1/2) * du). Integrating:
(u^(-1/2+1))/(-1/2+1) + c = (u^(1/2))/(1/2) + c = 2u^(1/2) + c = 2√u + c.
Put u = 1 + sin(x). Therefore, 2√(1 + sin(x)) + c. Therefore:
∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c!!!
