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3 years ago

Will chlorine water react with potassium fluoride solution? If not, why?

2 answers:

6 0

No chlorine will not react with potassium fluoride solution because chlorine reacts with water, forming HOCI and HCI. The only way for there to be a reaction when you add KF (Potassium Fluoride) to chlorine water is if there were any impurities in the water, even then it is doubtful that a color change would occur.

Dahasolnce [82]3 years ago

3 0

Answer : The chlorine water will not react with potassium fluoride solution because chlorine is less reactive halogen than the fluorine.

Explanation :

Displacement of halogen : If halogen is added to the solution of compound containing a less reactive halogen then it will react with compound and form a new product. This is also known as displacement reaction.

For example : Fluorine water react with sodium chloride solution to give sodium fluoride as chlorine water as a product.

The balanced chemical reaction will be:

$F_2(aq)+NaCl(aq)\rightarrow 2NaF(aq)+Cl_2(aq)$

In this reaction, a most reactive halogen (fluorine) displace a less reactive halogen (chlorine).

According to the question,

Chlorine water react does not react with potassium fluoride solution because chlorine is less reactive halogen than the fluorine. So, it will not displace fluorine halogen form the solution.

$Cl_2(aq)+KF(aq)\rightarrow \text{No reaction}$

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The kinetic energy of an object with a mass of 6.8 kg and a velocity of 5.0 m/s is [BLANK] J. (Report the answer to two signific

dmitriy555 [2]

<h2>Hello!</h2>

The answer is:

The kinetic energy of the object is equal to 85 J.

The kinetic energy involves the speed and the mass of an object in motion. We can calculate the following the work needed to speed an object (kinetic energy) using the equation:

$KineticEnergy=\frac{1}{2}mv^{2}$

Where,

m, is the mas of the object

v, is the speed of the object.

Now, we are given:

$mass=m=6.8kg\\speed=v=5\frac{m}{s}$

So, substituting and calculating the kinetic energy of the object, we have:

$KineticEnergy=\frac{1}{2}*6.8kg*(5\frac{m}{s})^{2}$

$KineticEnergy=\frac{1}{2}*6.8kg*(25\frac{m^{2}}{s^{2}})$

$KineticEnergy=\frac{1}{2}*170kg\frac{m^{2}}{s^{2}}$

$KineticEnergy=85kg\frac{m^{2}}{s^{2}}=85J$

We have that the kinetic energy of the object is equal to 85 J.

Have a nice day!

8 0

3 years ago

Read 2 more answers

2000, the Millennium Bridge, a new footbridge over the River Thames in London, England, was opened to the public. However, after

sweet [91]

Answer:

n = 1810

A = 25 mm

Explanation:

Given:

Lateral force amplitude, F = 25 N

Frequency, f = 1 Hz

mass of the bridge, m = 2000 kg/m

Span, L = 144 m

Amplitude of the oscillation, A = 75 mm = 0.075 m

time, t = 6T

now,

Amplitude as a function of time is given as:

$A(t)=A_oe^{\frac{-bt}{2m}}$

or amplitude for unforce oscillation

$\frac{A_o}{e}=A_oe^{\frac{-b(6T)}{2m}}$

$\frac{6bt}{2m}=1$

$b=\frac{m}{3T}$

Now, provided in the question Amplitude of the driven oscillation

$A=\frac{F_{max}}{\sqrt{(k-m\omega_d^2)+(b\omega_d^2)}}$

the value of the maximum amplitude is obtained $(k=m\omega_d^2)$

thus,

$A=\frac{F_{max}}{(b\omega_d}$

Now, for n people on the bridge

Fmax = nF

thus,

max amplitude

$0.075=\frac{nF}{((\frac{m}{3T})2\pi}$

n = 1810

hence, there were 1810 people on the bridge

b) $A=\frac{F_{max}}{(b\omega_d}$

since the effect of damping in the millenium bridge is 3 times

thus,

b=3b

therefore,

$A=\frac{F_{max}}{(3b\omega_d}$

$A=\frac{1}{(3}A_o$

$A=\frac{1}{(3}0.075$

A = 0.025 m = 25 mm

6 0

3 years ago

Monochromatic light is incident on a pair of slits that are separated by 0.220 mm. The screen is 2.60 m away from the slits. (As

Naddik [55]

Answer:

$\lambda = 1.667 nm$

$\theta = 0.8681^o$

Explanation:

From the question we are told that

The distance of separation is $d = 0.220 \ mm = 0.00022 \ m$

The is distance of the screen from the slit is $D = 2.60 \ m$

The distance between the central bright fringe and either of the adjacent bright $y = 1.97 cm = 1.97 *10^{-2}\ m$

Generally the condition for constructive interference is

$d sin \tha(\theta ) = n \lambda$

From the question we are told that small-angle approximation is valid here.

So $sin (\theta ) = \theta$

=> $d \theta = n \lambda$

=> $\theta = \frac{n * \lambda }{d }$

Here n is the order of maxima and the value is n = 1 because we are considering the central bright fringe and either of the adjacent bright fringes

Generally the distance between the central bright fringe and either of the adjacent bright is mathematically represented as

$y = D * sin (\theta )$

From the question we are told that small-angle approximation is valid here.

$y = D * \theta$

=> $\theta = \frac{ y}{D}$

$\frac{n * \lambda }{d } = \frac{y}{D}$

$\lambda =\frac{d * y }{n * D}$

substituting values

$\lambda = \frac{0.00022 * 1.97*10^{-2} }{1 * 2.60 }$

$\lambda = 1.667 *10^{-6}$

$\lambda = 1.667 nm$

In the b part of the question we are considering the next set of bright fringe so n= 2

Hence

$dsin (\theta ) = n \lambda$

$\theta = sin^{-1}[\frac{ n * \lambda }{d} ]$

$\theta = sin^{-1}[\frac{ 2 * 1667 *10^{-9}}{ 0.00022} ]$

$\theta = 0.8681^o$

7 0

4 years ago

What physical characteristic is the same for a particular substance regardless of the sample size .

jeka94

<span>The physical feel of H2O is the same regardless of the sample size of the substance. Water feels wet whether it is a single drop or equivalent in volume to an ocean. It is the way the substance feels no matter how much or how little there is present.</span>

4 0

4 years ago

A body of mass 5kg is taken from height 10m. find the increase in potential energy

Vadim26 [7]

Answer:

500 joule

Explanation:

given,

mass(m)= 5kg

height(h)= 10m

acceleration due to gravity(g)= 10m/s^2

potential energy =?

We know that,

potential energy = mgh

= 5×10×10

= 500 joule

3 0

3 years ago