Which of the following masses is the smallest?

Elephants can communicate over distances as far as 6 km by using very low-frequency sound waves. What is the wavelength of a 10

harkovskaia [24]

The characteristics of the sound waves allow to find the result for the wavelength is:

λ = 34.29 m

The sound wave is a longitudinal traveling wave, where the speed of the wave depends on the air temperature.

v = $v_o \sqrt{1 + \frac{T}{273} }$

where v₀ is the speed of sound for T = 0ºc v₀ = 331 m / s.

indicate that the temperature is T = 20ºC, let's find the speed of the traveling wave.

v = 331 $\sqrt{1 + \frac{20}{273} }$

v = 342.9 m / s

The speed of sound is related to wavelength and frequency.

v = λ f

λ = $\frac{v}{f}$

Let's calculate

$\lambda = \frac{342.29}{10}$

λ = 34.29 m

In conclusion using the characteristics of sound waves we can find the result for the wavelength is:

λ = 34.29 m

Learn more here: brainly.com/question/21995826

3 0

3 years ago

Burning a canful of petrol or dropping it. which is likely to release most energy?

Neporo4naja [7]

Answer:

Burning of canful of petrol will release more energy

Explanation:

If you like my answer than please mark me brainliest

5 0

3 years ago

PLEASE HELP! DUE DATE IS TODAY

g100num [7]

Answer:

Question 2

Part (a)

Chlorine: type of compound = chloride

Oxygen: type of compound = oxide

Part (b)

The iron reacts with water and oxygen to form rust.

A water molecule is made up of two hydrogen atoms joined to one oxygen atom: Di-hydrogen oxide.

Question 3

This circuit is in parallel.

The current in a parallel circuit splits into different branches then combines again before it goes back into the supply.

We are told that A₁ = 0.8 A

As the lamps have equal resistance, the current splits equally:

A₂ = 0.4 A

A₃ = 0.4 A

Then combines again:

A₄ = 0.8 A

4 0

2 years ago

The patellar tendon attaches to the tibia at a 20 deg angle 3 cm from the axis of rotation at the knee. If the force generated i

gregori [183]

Answer:

the resulting angular acceleration is 15.65 rad/s²

Explanation:

Given the data in the question;

force generated in the patellar tendon F = 400 N

patellar tendon attaches to the tibia at a 20° angle 3 cm( 0.03 m ) from the axis of rotation at the knee.

so Torque produced by the knee will be;

T = F × d⊥

T = 400 N × 0.03 m × sin( 20° )

T = 400 N × 0.03 m × 0.342

T = 4.104 N.m

Now, we determine the moment of inertia of the knee

I = mk²

given that; the lower leg and foot have a combined mass of 4.2kg and a given radius of gyration of 25 cm ( 0.25 m )

we substitute

I = 4.2 kg × ( 0.25 m )²

I = 4.2 kg × 0.0626 m²

I = 0.2625 kg.m²

So from the relation of Moment of inertia, Torque and angular acceleration;

T = I∝

we make angular acceleration ∝, subject of the formula

∝ = T / I

we substitute

∝ = 4.104 / 0.2625

∝ = 15.65 rad/s²

Therefore, the resulting angular acceleration is 15.65 rad/s²

8 0

3 years ago

you are piloting a small plane and you want to reach an airport 450 km due south in 3.0 h a wind is blowing from the west 50.0 k

alex41 [277]

Answer:

You should choose airspeed 158.11 km/h at 18.4° west of south

Explanation:

The distance to the air port is 450 km due to south

You should to reach the airport in 3 hours

→ Velocity = distance ÷ time

→ Distance = 450 km , time = 3 hours

→ The velocity of your plane = 450 ÷ 3 = 150 km/h due to south

A wind is blowing from west 50 km/h

We need to know what heading and airspeed you should choose to

reach your destination

At first we must find the resultant velocity of your plane and the wind

The south and west are perpendicular, then the resultant velocity is

→ $v_{R}=\sqrt{(v_{p})^{2}+(v_{w})^{2}}$

→ $v_{p}=150$ km/h , $v_{w}=50$ km/h

→ $v_{R}=\sqrt{(150)^{2}+(50)^{2}}=158.11$ km/h

To cancel the velocity of the wind, the pilot should maintain the velocity

of the plane at 158.11 km/h

The direction of the velocity is the angle between the resultant velocity

and the vertical (south)

→ The direction of the velocity is $tan^{-1}\frac{50}{150}=18.4$ °

The direction of the velocity is 18.4° west of south

You should choose airspeed 158.11 km/h at 18.4° west of south

8 0

3 years ago