Question

Determine the solutuon for x^2-3x-28>0

Answer 1

Answer:

 x < -4 or x > 7.

Step-by-step explanation:

We first determine the critical points by solving x^2 - 3x - 28 = 0:

x^2 - 3x - 28 = 0

(x - 7)(x + 4) = 0

x = 7, - 4

so the critical points are  -4 and  7.

Create a Table   (pos = positive and neg = negative):

Value  of           x< - 4        -4  < x < 7         x > 7    

---------------------|----------- |--------------------- |---------------------

x + 4                  NEG           POS                 POS

x - 7                    NEG           NEG                POS

(x + 4)(x - 7)         POS           NEG                POS

So the function is positive (>0) for x < -4 or x > 7.

You can also do this by drawing the graph of the function.