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3 years ago

Determine the solutuon for x^2-3x-28>0

Mathematics

1 answer:

natita [175]3 years ago

6 0

Answer:

x < -4 or x > 7.

Step-by-step explanation:

We first determine the critical points by solving x^2 - 3x - 28 = 0:

x^2 - 3x - 28 = 0

(x - 7)(x + 4) = 0

x = 7, - 4

so the critical points are -4 and 7.

Create a Table (pos = positive and neg = negative):

Value of x< - 4 -4 < x < 7 x > 7

---------------------|----------- |--------------------- |---------------------

x + 4 NEG POS POS

x - 7 NEG NEG POS

(x + 4)(x - 7) POS NEG POS

So the function is positive (>0) for x < -4 or x > 7.

You can also do this by drawing the graph of the function.

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