Answer:
1.41 m/s^2
Explanation:
First of all, let's convert the two speeds from km/h to m/s:
Now we find the centripetal acceleration which is given by
where
v = 12.8 m/s is the speed
r = 140 m is the radius of the curve
Substituting values, we find
we also have a tangential acceleration, which is given by
where
t = 17.0 s
Substituting values,
The two components of the acceleration are perpendicular to each other, so we can find the resultant acceleration by using Pythagorean theorem:
Answer:
t = 1.05 s
Explanation:
Given,
The distance between your vehicle and car, 100 ft
The constant speed of your vehicle, u = 95 ft/s
Since, the velocity is constant, a =0
If the car stopped suddenly, time left for you to hit the brake, t = ?
Using the second equation of motion,
S = ut + ½ at²
Substituting the given values in the equation
100 = 95 x t
t = 100/95
= 1.05 s
Hence, the time left for you to hit the brakes and stop before rear ending them, t = 1.05 s
In order to answer this exercise you need to use the formulas
S = Vo*t + (1/2)*a*t^2
Vf = Vo + at
The data will be given as
Vf = final velocity = ?
Vo = initial velocity = 1.4 m/s
a = acceleration = 0.20 m/s^2
s = displacement = 100m
And now you do the following:
100 = 1.4t + (1/2)*0.2*t^2
t = 25.388s
and
Vf = 1.4 + 0.2(25.388)
Vf = 6.5 m/s
So the answer you are looking for is 6.5 m/s
Answer: The answer is B. Add more solute (took test)
Explanation:
