Well, a curler uses heat to calm down friction so I am not sure
Answer:
write the equation of motion go over the centre of mass
Explanation:
the center of mass of a distribution of mass in space (sometimes referred to as the balance point) is the unique point where the weighted relative position of the distributed mass sums to zero. This is the point to which a force may be applied to cause a linear acceleration without an angular acceleration.
Answer:
<u>Distance</u><u> </u><u>between</u><u> </u><u>them</u><u> </u><u>is</u><u> </u><u>4</u><u>,</u><u>2</u><u>0</u><u>0</u><u> </u><u>meters</u><u>.</u>
Explanation:
Consinder car A:
![{ \bf{distance = speed \times time }}](https://tex.z-dn.net/?f=%7B%20%5Cbf%7Bdistance%20%3D%20%20speed%20%5Ctimes%20time%20%7D%7D)
substitute:
![distance = 20 \times (2 \times 60) \\ = 2400 \: m](https://tex.z-dn.net/?f=distance%20%3D%2020%20%5Ctimes%20%282%20%5Ctimes%2060%29%20%5C%5C%20%20%3D%202400%20%5C%3A%20m)
Consider car B:
![distance = 15 \times (2 \times 60) \\ = 1800 \: m](https://tex.z-dn.net/?f=distance%20%3D%2015%20%5Ctimes%20%282%20%5Ctimes%2060%29%20%5C%5C%20%20%3D%201800%20%5C%3A%20m)
since these cars move in opposite directions, distance between them is their summation:
![distance \: between = { \sum(distance \: of \: each \: car)} \\ = 2400 + 1800 \\ = 4200 \: m](https://tex.z-dn.net/?f=distance%20%5C%3A%20between%20%3D%20%7B%20%5Csum%28distance%20%5C%3A%20of%20%5C%3A%20each%20%5C%3A%20car%29%7D%20%5C%5C%20%20%3D%202400%20%2B%201800%20%5C%5C%20%20%3D%204200%20%5C%3A%20m)
It would either break or stop depends on the density
Answer:
a) The charge of the capacitor is 4.25x10⁻¹¹C
b) The charge of the capacitor is 4.25x10⁻¹¹C because the battery is disconnected.
c) The potential difference across the plates is 18 V
d) The work is 7.64x10⁻¹⁰J
Explanation:
The capacitance of the capacitor is equal to:
![C=\frac{e_{0}A }{d}](https://tex.z-dn.net/?f=C%3D%5Cfrac%7Be_%7B0%7DA%20%7D%7Bd%7D)
A = 2 cm² = 0.0002 m²
d = 0.5 mm = 0.0005 m
Replacing:
![C=\frac{8.85x10^{-12}*0.0002 }{0.0005} =3.54x10^{-12} F = 3.54pF](https://tex.z-dn.net/?f=C%3D%5Cfrac%7B8.85x10%5E%7B-12%7D%2A0.0002%20%7D%7B0.0005%7D%20%3D3.54x10%5E%7B-12%7D%20F%20%3D%203.54pF)
a) The charge of the capacitor is equal to:
Q = C*V = 3.54 * 12 = 42.48 pC = 4.25x10⁻¹¹C
b) The charge is the same because the battery is disconnected (Q = 4.25x10⁻¹¹C)
c) If distance is increased, we have:
![C=\frac{8.85x10^{-12}*0.0002 }{0.00075} =2.36x10^{-12} F=2.36pF](https://tex.z-dn.net/?f=C%3D%5Cfrac%7B8.85x10%5E%7B-12%7D%2A0.0002%20%7D%7B0.00075%7D%20%3D2.36x10%5E%7B-12%7D%20F%3D2.36pF)
The potential is:
![V=\frac{Q}{C} =\frac{42.48}{2.36} =18V](https://tex.z-dn.net/?f=V%3D%5Cfrac%7BQ%7D%7BC%7D%20%3D%5Cfrac%7B42.48%7D%7B2.36%7D%20%3D18V)
d) The work done is equal to:
![W=VQ=18*42.48=764.6pJ=7.64x10^{-10} J](https://tex.z-dn.net/?f=W%3DVQ%3D18%2A42.48%3D764.6pJ%3D7.64x10%5E%7B-10%7D%20J)