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Damm [24]
4 years ago
3

Select the characteristics that will probably yield an ionic bond. Each answer refers to two atoms, Atom X and Atom Y. Atom X is

referred to first, and Atom Y is referred to second. low E.N., low E.N. high E.N., low E.N. high E.N., high E.N. low I.E., low I.E. low I.E., high I.E. high I.E., high I.E.
Chemistry
2 answers:
atroni [7]4 years ago
7 0

Answer:

Low I.E of atom X and high I.E of atom Y.

Explanation:

An ionic bond is formed when two ions are formed.

In ionic bond an atom loses electron and the electron is accepted by another atom. The atom losing electron acquires positive charge and the atom gaining electron acquires negative charge.

Now to lose an electron the atom should have low ionization energy (I.E.) and the other atom must not lose electron easily (high I.E.) and should have high electron affinity.

mel-nik [20]4 years ago
3 0

Answer:

low I.E., high I.E

Explanation:

Ionic or electrovalent bonds are interatomic bonds that results from the transfer of electrons between atoms. It is usually between a metal, electron donor, and non-metals which accepts electrons readily.

For an ionic bond to be formed, a large electronegativity difference is required. This suggests that one atom has a large electronegativity value while the other, the donating atom, has a low value of electronegativity. Electronegativity of an element is a property that combines the ability of its atom to lose or gain electrons. So, with respect to electronegativity, atom X would have a low electronegativity value and Y, a very high electronegativity value.

Ionization Energy(I. E) is the readiness of an atom to lose an electron. Most metals have low I.E values and would readily want to lose electrons. This satisfies X. Y in an ionic bond would have a very high I.E value and would not readily want to lose electrons but gain electrons. Y is a non-metal to a large extent.

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