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The molar mass of K is 39, Cr is 52, and O is 16. The rough calculation of these numbers are 294.
Answer : The heat of the reaction is, 1.27 kJ/mole
Explanation :
First we have to calculate the heat released.
Formula used :
or,
where,
Q = heat = ?
m = mass of sample = 1.50 g
c = specific heat of water =
= initial temperature =
= final temperature =
Now put all the given value in the above formula, we get:
Now we have to calculate the heat of the reaction in kJ/mol.
where,
= enthalpy change = ?
Q = heat released = 0.0238 kJ
n = number of moles NH₄NO₃ =
Therefore, the heat of the reaction is, 1.27 kJ/mole
<u>Answer:</u> The molar concentration of NaOH in the final diluted solution is 0.056 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
Given mass of NaOH = 4.00 g
Molar mass of NaOH = 40 g/mol
Volume of solution = 5.00 mL
Putting values in above equation, we get:
To calculate the molarity of the diluted solution, we use the equation:
where,
are the molarity and volume of the concentrated NaOH solution
are the molarity and volume of diluted NaOH solution
We are given:
Putting values in above equation, we get:
Hence, the molar concentration of NaOH in the final diluted solution is 0.056 M
Answer:stomach acidExplanation:try lngss