Answer:
334.08 g
Explanation:
87 proof = 43.5%
in 1L of liquid there is 43.5% alcohol/ethanol
1L (43.5/100) = 0.435 L alcohol
we want density in g/L because that's the volume u have
density 0.798 g/mL = 798 g/L
multiply the volume of alcohol by its density to get grams
0.435 L(798 g/L) = 334.08 g
Answer:
I think its Female
Explanation:
Correct me if I was wrong :)
Answer:
6H20 represents six molecules of water
Answer:
779 g of chlorine would produce 7.3 moles of AlCl₃
Explanation:
Given data:
Mass of chlorine gas = 779 g
Number of moles of Aluminium chloride formed = ?
Solution:
Chemical equation:
2AlBr₃ + 3Cl₂ → 2AlCl₃ + 3Br₂
<em>Number of moles of chlorine:</em>
Number of moles = mass/ molar mass
Number of moles = 779 g/ 71 g/mol
Number of moles = 11 mol
Now we will compare the moles of chlorine with Aluminium chloride.
Cl₂ : AlCl₃
3 : 2
11 : 2/3×11 = 7.3 mol
779 g of chlorine would produce 7.3 moles of AlCl₃.