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lidiya [134]
3 years ago
11

If the accepted value for the density of rubber is 1.15 g/mL, what is your percent error for each rubber

Chemistry
1 answer:
Anastasy [175]3 years ago
7 0

Answer:

4.34%

Explanation:

The  accepted value for the density of rubber is 1.15 g/mL

Let the calculated value for the density of rubber is 1.2 g/mL

We need to find the percent error for rubber stopper. It can be calculated as follows :

\text{Error}=\dfrac{|\text{actual value-calculated value}|}{\text{actual value}}\times 100\\\\\text{Error}=\dfrac{1.15-1.2}{1.15}\times 100\\\\\text{Error}=4.34\%

<h2>So, the percent error for the density of rubber is 4.34%.</h2>
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A _____ solution contains more dissolved solute than a saturated solution at the same temperature.
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- How many grams are in 4.6 x 1016 molecules of phosphorus trichloride (PCI)?
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0.0000101 grams.

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They are three chlorine atoms and one phosphorus atom. So you do this.

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Now use dimensional analysis to show your work

4.6 x 10^16 grams of PCl3 * 1 mol/ 6.02 x 10^23 * 137.5 g/mol / 1 mol

The grams and the moles cancel out.

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4.6 has the fewest digits which is 2.

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0.000010507 rounds to 0.0000101

So the final answer is 0.0000101 grams(don't forget the units)

Hope it helped!

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All known elements are grouped together in the periodic table of elements into groups with related properties. It becomes a crucial tool for chemists, nanotechnologists, and other scientists as a result. You can forecast how chemicals will react if you learn to use and comprehend the periodic table.

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