The balanced reaction is:
<span>2Al (s) + 3Fe(NO3)2 (aq) = 3Fe (s) + 2Al(NO3)3 (aq)
</span>
We are given the amount of <span>iron (II) nitrate solution with its purity. This will be the starting point of our calculation.
265 (.845) gram </span>iron (II) nitrate (1 mol Fe(NO3)2 / 179.85 g Fe(NO3)2) ( 3 mol Fe / 3 mol <span>Fe(NO3)2) (55.85 g Fe / 1 mol Fe) = 69.54 g Fe</span>
L think the answer is kc=:02:-3
For #1, I'd say it's "It will usually bond to multiple atoms which can provide a total of 4 additional electrons."
2. Ionic (I'm quite certain because anions/cations (-1 & +1) are Ionic from what I recall, if that's true it's Ionic.
3. "comparison of the associated families to which the elements belong" and
"the difference in electronegativities" are what I would choose, as I mentioned in a comment earlier.
If I'm wrong let me know, but I am at least 80% sure that these responses are correct from what I remember in Chemistry.