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anzhelika [568]
3 years ago
13

Help me please!!!!!!

Chemistry
1 answer:
Bingel [31]3 years ago
7 0

Answer:

CH₄ + 2O₂ –> CO₂ + 2H₂O

The coefficients are: 1, 2, 1, 2

Explanation:

CH₄ + O₂ –> CO₂ + H₂O

The above equation can be balance by as follow:

CH₄ + O₂ –> CO₂ + H₂O

There are 4 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 2 before H₂O as shown below:

CH₄ + O₂ –> CO₂ + 2H₂O

There are 2 atoms of O on the left side and a total of 4 atoms on the right side. It can be balance by writing 2 before O₂ as shown below:

CH₄ + 2O₂ –> CO₂ + 2H₂O

Now, the equation is balanced.

The coefficients are: 1, 2, 1, 2

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The better era tbh.......
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Calculate the number of oxygen atoms and its mass in 50g of CaCo3<br>​
xz_007 [3.2K]

The number of oxygen atoms = 3

Mass = 24 g

<h3>Further explanation</h3>

The formula of a compound shows the composition of the constituent elements

CaCO₃ is composed of 3 types of elements, namely Ca, C and O

The amounts of each of these elements in the compound CaCO₃:

  • Ca = 1
  • C = 1
  • O = 3

So the number of oxygen atoms = 3

mass of Oxygen :

\tt mass~O=\dfrac{3\times Ar~O}{MW~CaCO_3}\times mass~CaCO_3\\\\mass~O=\dfrac{3\times 16}{100}\times 50=24~g

5 0
3 years ago
An artifact originally had 16 grams of​ carbon-14 present. the decay model upper a equals 16 e superscript negative 0.000121 ta=
xeze [42]

<u>Given:</u>

Initial amount of carbon, A₀ = 16 g

Decay model = 16exp(-0.000121t)

t = 90769076 years

<u>To determine:</u>

the amount of C-14 after 90769076 years

<u>Explanation:</u>

The radioactive decay model can be expressed as:

A = A₀exp(-kt)

where A = concentration of the radioactive species after time t

A₀ = initial concentration

k = decay constant

Based on the given data :

A = 16 * exp(-0.000121*90769076) = 16(0) = 0

Ans: Based on the decay model there will be no C-14 left after 90769076 years

3 0
3 years ago
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What is the thermal energy needed to completely melt 9.60 mol of ice at 0.0 C
inysia [295]
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        Explanation
ice  melt  to  form   water

The molar  heat of fusion  for   water  is  6.02  Kj/mol
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=9.6  mol  x6.02 kj/mol =57.8  Kj
4 0
3 years ago
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Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔
Vilka [71]

Answer : The correct option is, (C) 1.1

Solution :  Given,

Initial moles of N_2O_4 = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration N_2O_4.

\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}

\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M

The given equilibrium reaction is,

                           N_2O_4(g)\rightleftharpoons 2NO_2(g)

Initially                      c                 0

At equilibrium   (c-c\alpha)           2c\alpha

The expression of K_c will be,

K_c=\frac{[NO_2]^2}{[N_2O_4]}

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

where,

\alpha = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}

K_c=1.066\aprrox 1.1

Therefore, the value of equilibrium constant for this reaction is, 1.1

4 0
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