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k0ka [10]
3 years ago
5

(-5x^2+7x+1) - (8x^2+x-10)

Mathematics
2 answers:
Nata [24]3 years ago
6 0

Answer:

13x^2+8x-9

Step-by-step explanation:

KengaRu [80]3 years ago
3 0
-13x^2+8x-9 what’s your answer
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The top and bottom margins of a poster are each 15 cm and the side margins are each 10 cm. If the area of printed material on th
12345 [234]

Answer:

the dimension of the poster = 90 cm length and 60 cm  width i.e 90 cm by 60 cm.

Step-by-step explanation:

From the given question.

Let p be the length of the of the printed material

Let q be the width of the of the printed material

Therefore pq = 2400 cm ²

q = \dfrac{2400 \ cm^2}{p}

To find the dimensions of the poster; we have:

the length of the poster to be p+30 and the width to be \dfrac{2400 \ cm^2}{p} + 20

The area of the printed material can now be:  A = (p+30)(\dfrac{2400 }{p} + 20)

=2400 +20 p +\dfrac{72000}{p}+600

Let differentiate with respect to p; we have

\dfrac{dA}{dp}= 20 - \dfrac{72000}{p^3}

Also;

\dfrac{d^2A}{dp^2}= \dfrac{144000}{p^3}

For the smallest area \dfrac{dA}{dp }=0

20 - \dfrac{72000}{p^2}=0

p^2 = \dfrac{72000}{20}

p² = 3600

p =√3600

p = 60

Since p = 60 ; replace p = 60 in the expression  q = \dfrac{2400 \ cm^2}{p}   to solve for q;

q = \dfrac{2400 \ cm^2}{p}

q = \dfrac{2400 \ cm^2}{60}

q = 40

Thus; the printed material has the length of 60 cm and the width of 40cm

the length of the poster = p+30 = 60 +30 = 90 cm

the width of the poster = \dfrac{2400 \ cm^2}{p} + 20 = \dfrac{2400 \ cm^2}{60} + 20  = 40 + 20 = 60

Hence; the dimension of the poster = 90 cm length and 60 cm  width i.e 90 cm by 60 cm.

4 0
3 years ago
|1/4 x +2| -3 =5 solve for x and graph on number line
kaheart [24]

The value of x on the number line is 24 and - 40

A number line in elementary mathematics is a representation of a graduated straight line that acts as an abstraction for real numbers, represented by the letter R. It is assumed that every point on a number line corresponds to a real number, and that every real number corresponds to a point.

When seen as a geometric space, namely the one-dimensional Euclidean space, the number line, also known as a real line in advanced mathematics, is technically defined as the set R of all real numbers. It can be conceptualized as a linear continuum, metric space, topological space, vector space (or affine space), measure space, or topological space.

The given equation is

|\frac{1}{4}x+2 | -3=5

Solving the equation:

or,|\frac{1}{4}x+2 | =5+3\\or,|\frac{1}{4}x+2 |=8\\or,\frac{1}{4}x+2=\pm8\\or,x+8=\pm32\\or,x=-8\pm32

Now we take the two separate values of x:

either x=-8+32 or x=-8-32

or,x=24 or x=-40

The value of x is 24 and - 40.

To learn more about number line:

brainly.com/question/24644930

#SPJ9

7 0
1 year ago
Can somebody help me with this. Will mark brainliest.
Monica [59]

Answer:

15.9

Step-by-step explanation:

3 0
2 years ago
Find the y-intercept and the slope of the line.<br> 6x-2y=5
solmaris [256]

Answer:

m=3

b=(0,5)

Step-by-step explanation:

6 0
1 year ago
3x - 2(6 - x) = 7x + 2(5 + x) - 6<br> What is the answer
mafiozo [28]

Answer:

x= -4

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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