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PolarNik [594]
3 years ago
9

PLEASE HELP ASAP I GIVE YOU BRAINLIEST AND 20 POINTS

Mathematics
1 answer:
Contact [7]3 years ago
8 0

Answer:

No

Step-by-step explanation:

Inconsistent means it has no solution, which means they do not intersect

Dependent means it is the same line

You cannot have both the same line and not intersecting.

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Please solve this <br>Solve by completing the square. 4x2+8x−3=0
Greeley [361]

Step-by-step explanation:

4x2+8x−3=0

For this equation: a=4, b=8, c=-3

4x2+8x+−3=0

Step 1: Use quadratic formula with a=4, b=8, c=-3.

x=

−b±√b2−4ac

2a

x= −(8)±√(8)2−4(4)(−3)

2(4)

x= −8±√112

8  x=−1+

1 2 √7 or x=−1+

−1 2 √7

Answer:  x=−1+

1 2√7 or x=−1+

−1 2 √7

7 0
2 years ago
A packet contains 10 sweets.
Tresset [83]

Answer:

2 peoples

Step-by-step explanation:

both of them will 5 sweets

4 0
3 years ago
Read 2 more answers
Find the volume v of the described solid s. the base of s is an elliptical region with boundary curve 4x2 + 9y2 = 36. cross-sect
Tasya [4]
4x^2+9y^2=36\iff\dfrac{x^2}9+\dfrac{y^2}4=1

defines an ellipse centered at (0,0) with semi-major axis length 3 and semi-minor axis length 2. The semi-major axis lies on the x-axis. So if cross sections are taken perpendicular to the x-axis, any such triangular section will have a base that is determined by the vertical distance between the lower and upper halves of the ellipse. That is, any cross section taken at x=x_0 will have a base of length

\dfrac{x^2}9+\dfrac{y^2}4=1\implies y=\pm\dfrac23\sqrt{9-x^2}
\implies \text{base}=\dfrac23\sqrt{9-{x_0}^2}-\left(-\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac43\sqrt{9-{x_0}^2}

I've attached a graphic of what a sample section would look like.

Any such isosceles triangle will have a hypotenuse that occurs in a \sqrt2:1 ratio with either of the remaining legs. So if the hypotenuse is \dfrac43\sqrt{9-{x_0}^2}, then either leg will have length \dfrac4{3\sqrt2}\sqrt{9-{x_0}^2}.

Now the legs form a similar triangle with the height of the triangle, where the legs of the larger triangle section are the hypotenuses and the height is one of the legs. This means the height of the triangular section is \dfrac4{3(\sqrt2)^2}\sqrt{9-{x_0}^2}=\dfrac23\sqrt{9-{x_0}^2}.

Finally, x_0 can be chosen from any value in -3\le x_0\le3. We're now ready to set up the integral to find the volume of the solid. The volume is the sum of the infinitely many triangular sections' areas, which are

\dfrac12\left(\dfrac43\sqrt{9-{x_0}^2}\right)\left(\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac49(9-{x_0}^2)

and so the volume would be

\displaystyle\int_{x=-3}^{x=3}\frac49(9-x^2)\,\mathrm dx
=\left(4x-\dfrac4{27}x^3\right)\bigg|_{x=-3}^{x=3}
=16

6 0
3 years ago
What is 4 1/3 + (5+6 2/3) ?
Vitek1552 [10]

Answer:

16

Step-by-step explanation:

do the parenthesis first, you get 11 2/3 from that. Then do 4 1/3 + 11 2/3, you get 16

6 0
4 years ago
Read 2 more answers
Simplify. (-4x^4+x^2-4)+(5x^2-4)(−4x ​4 ​​ +x ​2 ​​ −4)+(5x ​2 ​​ −4)
zloy xaker [14]
-4x^4 - 15x^2 + 1 - 19/x^2 is your answer

Hope I helped :)
8 0
3 years ago
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