Your answer would be 24, so you got it right.
This is because you need to find the lowest common multiple of 6 and 8, that is, the lowest number that divides by both 6 and 8.
We can do this by either writing out the multiples of 6 and 8 until you find a common one, or you can find the prime factors of 6 and 8 and multiply them:
6-> 3 × 2
8-> 2 × (4)->2 × 2
So we would need to do 3 × 2 × 2 × 2 = 3 × 8 = 24
I hope this helps!
Step-by-step explanation:
(2a+3b)(4a²-6ab+9b²
(2a+3b){(2a)²-2a×3b+(3b)²}
Because (a³+b³)=(a+b)(a²-ab+b²)
Therefore,
(2a+3b){(2a)²-2a×3b+(3b)²}
=(2a)³+(3b)³
By substituting the values , we get
- (2a)³+(3b)³
- (2×3)³+(3×(-5))³
- 6³+(-15)³
- 216+(-3375)
- 216-3375
- -3159
Answer:
BC is 10 unit
BD is 15 units
Step-by-step explanation:
Here, given the end points of the line segments, we want to calculate BD and DC
Mathematically, the distance between two points can be calculated using the formula;
D = √(x2-x1)^2 + (y2-y1)^2
For BD, we have the following
D = √(14-5)^2 + (14-2)^2
D = √(9)^2 + 12^2
D = √81 + 144
D = √(225)
Distance BD is 15 units
For BC, we have the following
D = √(11-5)^2 + (10-2)^2
D = √(6)^2 + 8^2
D = √100
D = 10
The answer is -5/8 because if you divide you get -.625
