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alisha [4.7K]
2 years ago
6

-3a + 3 > 33 + -15 -14 -13 -12 -11 -10 9 -3

Mathematics
1 answer:
alukav5142 [94]2 years ago
3 0

Answer:

its 222

Step-by-step explanation: I think :) haha\

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Will give brainliest if you get this right!
SSSSS [86.1K]

The answer is x=6. I double checked the work and am 100% sure thats the answer

7 0
3 years ago
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Without using logarithm tables, find the value of x given that: 2log2/3 = 1/2logx - log 18 + log 16
sweet-ann [11.9K]

Answer:

x=\frac{1}{4}

Step-by-step explanation:

<u>Given:</u>

2log(\frac{2}{3})=\frac{1}{2}log(x)-log(18)+log(16)

<u>Use the Power Rule Law:</u>

log(\frac{2}{3}^2)=log(x^{1/2})+log(16)-log(18)

<u>Use the Quotient Rule Law:</u>

log(\frac{4}{9})=log(\sqrt{x})+log(\frac{16}{18})

<u>Use the Product Rule Law:</u>

log(\frac{4}{9})=log(\frac{16\sqrt{x}}{18})

<u>Simplify:</u>

log(\frac{4}{9})=log(\frac{8\sqrt{x}}{9})

\frac{4}{9}=\frac{8\sqrt{x}}{9}

4=8\sqrt{x}

\frac{4}{8}=\sqrt{x}

\frac{1}{2}=\sqrt{x}

\frac{1}{4}=x

5 0
2 years ago
Akram ed a busniess with rs 70000.After 3months Aslam joined the busniess with rs 40000 and after 6months Asghar also invested r
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Answer:

11858 for akram

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6776 for asghar

7 0
2 years ago
15 ÷ 3 = Δ
Vlada [557]

Answer:

A)5 is the answer

Step-by-step explanation:

this is the answer

7 0
3 years ago
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Solve the system by using a matrix equation (Picture provided)
Katyanochek1 [597]

Answer:

Option b is correct (8,13).

Step-by-step explanation:

7x - 4y = 4

10x - 6y =2

it can be represented in matrix form as\left[\begin{array}{cc}7&-4\\10&-6\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}4\\2\end{array}\right]

A= \left[\begin{array}{cc}7&-4\\10&-6\end{array}\right]

X= \left[\begin{array}{c}x\\y\end{array}\right]

B= \left[\begin{array}{c}4\\2\end{array}\right]

i.e, AX=B

or X= A⁻¹ B

A⁻¹ = 1/|A| * Adj A

determinant of A = |A|= (7*-6) - (-4*10)

                                    = (-42)-(-40)

                                    = (-42) + 40 = -2

so, |A| = -2

Adj A=  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]

A⁻¹ =  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]/ -2

A⁻¹ =  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right]

X= A⁻¹ B

X=  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right] *\left[\begin{array}{c}4\\2\end{array}\right]

X= \left[\begin{array}{c}(3*4) + (-2*2)\\(5*4) + (-7/2*2)\end{array}\right]

X= \left[\begin{array}{c}12-4\\20-7\end{array}\right]

X= \left[\begin{array}{c}8\\13\end{array}\right]

x= 8, y= 13

solution set= (8,13).

Option b is correct.

3 0
3 years ago
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