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Mekhanik [1.2K]
3 years ago
10

3. How much work is done when you pull a 6 N wagon for 5 meters?

Physics
1 answer:
8090 [49]3 years ago
3 0

Answer:

<h2>30 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question

force = 6 N

distance = 5 m

We have

workdone = 6 × 5 = 30

We have the final answer as

<h3>30 J</h3>

Hope this helps you

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Gold is the most ductile of all metals. For example, one gram of gold can be drawn into a wire 2.05 km long. The density of gold
arsen [322]

Answer:

Resistance of gold wire, R=1977 \times 10^3 ohm

Explanation:

In this question we have given

Density of gold, d=19.3\times 10^3 \frac{kg}{m^3}

resistivity of gold, r=2.44\times 10^{-8} ohm.m

Length of wire, L= 2.05 km

Temperature, T= 20^oC

We know that relation between volume and density is given as

Density= \frac{mass}{Volume}

Therefore, volume occupied by one gram gold is given as,

V=\frac{.001 kg}{19.3\times 10^3 Kg m^{-3}} = 5.181\times 10^{-8} m^3.........(1)

We Know that Volume of gold wire which is cylindrical in shape is given by following formula

V=\pi \times r^2 \times L......(2)

Here,

A= \pi \times r^2...........(3)

here A is the cross sectional area of cylendrical gold wire  

From equation 2 and 3

we got

V=A \times L...............(4)

on comparing equation 1 and equation 4, we got,

A \times L=5.181\times 10^{-8} m^3

A=\frac{5.181\times 10^{-8} m^3}{2050 m}

A=2.53\times 10^{-11}m^2

we know that resistance and resistivity are related by following formula,

Resistance = resistivity\times \frac{L}{A}................(5)

Put values of resistivity, A and L in equation 5, we got

R = \frac{2.44 \times 10^{-8} ohm.m \times 2050 m}{2.53\times 10^{-11} m^2}

R=1977 \times 10^3 ohm

Therefore resistance of gold wire, R=1977 \times 10^3 ohm

7 0
3 years ago
A clever inventor claims to be able to make an electric car that makes its own electricity and never needs gas. The inventor cla
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Answer:

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Answer:

Its the first one

Explanation:

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