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3 years ago

Select the correct answer.

Physics

1 answer:

Sergeeva-Olga [200]3 years ago

8 0

Answer:

All of the above.

Explanation:

All of these steps are useful towards getting a job.

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The intensity of a sound wave increases as the wave spreads out from the source of the sound. True or false

ludmilkaskok [199]

Answer:False

Explanation:

the intensity of the sound wave decreases with increasing distance from the source.

3 0

3 years ago

8) 8 resistor is connected in **parallel** with a 6 resistor. This

lyudmila [28]

Answer:

The equivalent resistance of the combination is 3.42 ohms.

Explanation:

We have,

8 ohms resistor is connected in parallel with a 6 ohms resistor. It is required to find the equivalent resistance of this combination.

For a parallel combination, the equivalent resistance is given by :

$\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}$

Plugging the values of R₁ and R₂, we get :

$\dfrac{1}{R_{eq}}=\dfrac{1}{8}+\dfrac{1}{6}\\\\R_{eq}=3.42\ \Omega$

So, the equivalent resistance of the combination is 3.42 ohms.

4 0

3 years ago

The ability of sculptural material to resist forces of pressure, like gravity, is called its __________.

Vitek1552 [10]

I think the answer would be tensile, I’m sorry if it’s wrong

3 0

3 years ago

A student calculates the density of a copper cube to be 4.15 g/cm . If the accepted value is 8.64 g/cm the percentage error in h

Helen [10]

The percentage error in his experimental value is -51.97%.

<h3>What is percentage error?</h3>

This is the ratio of the error to the actual measurement, expressed in percentage.

To calculate the percentage error of the student, we use the formula below.

Formula:

Error(%) = (calculated value-accepted value)100/(accepted............. Equation 1

From the question,

Given:

Calculated value = 4.15 g/cm
accepted value = 8.64 g/cm

Substitute these values into equation 1

Error(%) = (4.15-8.64)100/8.64
Error(%) = -4.49(100)/8.64
Error(%) = -449/8.64
Error(%) = -51.97 %

Hence, The percentage error in his experimental value is -51.97%.

Learn more percentage error here: brainly.com/question/5493941

8 0

3 years ago

When a golfer tees off, the head of her golf club which has a mass of 158 g is traveling 48.2 m/s just before it strikes a 46.0

adoni [48]

Answer:

v₂ = 53.23 m/s

Explanation:

Given that,

The mass of a golf club, m₁ = 158 g = 0.158 kg

The initial speed of a golf club, u₁ = 48.2 m/s

The mass of a golf ball, m₂ = 46 g = 0.046 kg

It was at rest, u₂ = 0

Immediately after the collision, the club head continues to travel in the same direction but at a reduced speed of 32.7 m/s, v₁ = 32.7 m/s

We use the conservation of energy to find the speed of the golf ball just after impact as follows :

$m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\\v_2=\dfrac{m_1u_1-m_1v_1}{m_2}\\\\v_2=\dfrac{0.158(48.2)-0.158(32.7)}{0.046}\\\\=53.23\ m/s$

So, the speed of the golf ball just after the impact is equal to 53.23 m/s.

3 0

3 years ago