Answer:
Magnetic field, 
Explanation:
It is given that,
Number of turns, N = 320
Radius of the coil, r = 6 cm = 0.06 m
The distance from the center of one coil to the electron beam is 3 cm, x = 3 cm = 0.03 m
Current flowing through the coils, I = 0.5 A
We need to find the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils. The magnetic field midway between the coils is given by :
B = 0.00239 T
or
So, the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils is 
. Hence, this is the required solution.
Answer:
1000 N
Explanation:
The magnitude of the electrostatic force between two charged object is given by
where
k is the Coulomb constant
q1, q2 is the magnitude of the two charges
r is the distance between the two objects
Moreover, the force is:
- Attractive if the two forces have opposite sign
- Repulsive if the two forces have same sign
In this problem:
are the two charges
r = 3000 m is their separation
Therefore, the electric force between the charges is:
Answer:
force=1250kg * 30m/s+10
Explanation: it's a change in acceleration
Answer:
the ratio of the heat rejected to the cold reservoir for the improved engine to that for the original engine is 0.68
Explanation:
Given information
initial efficiency, η
= 0.28
final efficiency, η
= 0.51
ratio of the heat rejected = (1 - η)/(1 - η)
= (1 - 0.51)/(1 - 0.28)
= 0.68
