Answer:
Sulfuric acid + Zinc = reactant
Zinc sulfate + hydrogen = product
Lead oxide + carbon = reactant
lead + carbondioxide = product
Explanation:
Chemical equation:
Sulfuric acid + Zinc → Zinc sulfate + hydrogen
H₂SO₄ + Zn → ZnSO₄ + H₂
In this reaction sulfuric acid and zinc react to produce the zinc sulfate and hydrogen. That's why sulfuric acid and zinc are reactant. While zinc sulfate and hydrogen are products.
2nd reaction:
Lead oxide + carbon → lead + carbondioxide
2PbO + C → 2Pb + CO₂
In this reaction Lead oxide and carbon react to produce the lead and carbondioxide. That's why Lead oxide and carbon are reactant. While lead and carbondioxide are products.
Answer:
Half-reactions:
Cr³⁺ + 1e⁻ → Cr²⁺; Zn → Zn²⁺ + 2e⁻
Net ionic equation:
2Cr³⁺ + Zn → 2Cr²⁺ + Zn²⁺
Explanation:
The Cr³⁺ is reduced to Cr²⁺:
<h3>
Cr³⁺ + 1e⁻ → Cr²⁺ -Half-reaction 1-</h3>
Zn is oxidized to Zn²⁺:
<h3>
Zn → Zn²⁺ + 2e⁻ -Half-reaction 2-</h3>
Twice the reduction of Cr:
2Cr³⁺ + 2e⁻ → 2Cr²⁺
Now this reaction + Oxidation of Zn:
2Cr³⁺ + 2e⁻ + Zn → 2Cr²⁺ + Zn²⁺ + 2e⁻
<h3>2Cr³⁺ + Zn → 2Cr²⁺ + Zn²⁺ - Net ionic equation</h3>
To solve this problem, use Boyle's Law, which states that the relationship between pressure and volume are inversely proportional.
Boyle's Law: P1 * V1 = P2 * V2
We are given the starting volume, and both pressures, so we can plug those numbers in.
(.428) * (2.5) = (.724) * (V2)
To solve for V2 first simplify:
1.07 = (.724) * V2
Then divide both sides by .724 to leave V2 behind
V2 = 1.478 (Rounded to 3 decimal places)
So the final volume is 1.478L
Answer:
The answer is <em><u>A</u></em>.
Cations are formed when an atom or group of atom loses one or more electrons. The resulting species has more protons than electrons, so it has an overall positive charge.
Answer:
<u>O-H</u><u> </u><u>F-H</u><u> </u><u>N-Hy</u>
Explanation:
<u>C-H</u><u> </u><u>N-H</u><u> </u><u>O-</u><u>H</u><u> </u><u>F-</u><u>H</u>
