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zalisa [80]
3 years ago
6

The pressure exerted on a 2.5L sample of hydrogen gas at a constant temperature is increased from 0.428 atm to 0.724. What will

the final Volume be
Chemistry
1 answer:
garik1379 [7]3 years ago
6 0

To solve this problem, use Boyle's Law, which states that the relationship between pressure and volume are inversely proportional.

Boyle's Law: P1 * V1 = P2 * V2

We are given the starting volume, and both pressures, so we can plug those numbers in.

(.428) * (2.5) = (.724) * (V2)

To solve for V2 first simplify:

1.07 = (.724) * V2

Then divide both sides by .724 to leave V2 behind

V2 = 1.478 (Rounded to 3 decimal places)

So the final volume is 1.478L

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4 years ago
You need a 20% alcohol solution. on hand, you have a 240 ml of a 15% alcohol mixture. you also have 40% alcohol mixture. how muc
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0.15*240=36 ml of alcohol in <span>240 ml of a 15% alcohol mixture
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3 years ago
Soda is a mixture. The ingredients list for a can of soda is given below.
Rasek [7]

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6 0
3 years ago
Read 2 more answers
How many grams of water are produced from the decomposition of 63 grams of lithium hydroxide
Ymorist [56]

Answer:

18.65004 grams H2O

Explanation:

First, we need to write down the balanced chemical equation for the decomposition reaction:

2LiOH -> H2O + Li2O

Since we have grams of LiOH and we need to know the grams of water, we need to convert to moles since we can only compare moles to moles.

The amu of LiOH is 23.947.

The given grams of LiOH is 63.. To convert to moles, we will divide 63 by 23.947..

This gives us 2.6310 moles LiOH..

To convert to moles of H2O (and later grams of H2O), we will use the mole fractions from the balanced equation...

When we look at the balanced equation we can see that 2 moles of LIOH can produce 1 mol of Water, so:

2.6310 moles * \frac{1 molH_{2}O}{2 mol LiOH} = 1.3155 moles H2O

Now we will convert from moles to grams (we must multiply by the amu)

1.3155 moles H2O = 18.65 grams H2O

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3 years ago
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