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zalisa [80]
3 years ago
6

The pressure exerted on a 2.5L sample of hydrogen gas at a constant temperature is increased from 0.428 atm to 0.724. What will

the final Volume be
Chemistry
1 answer:
garik1379 [7]3 years ago
6 0

To solve this problem, use Boyle's Law, which states that the relationship between pressure and volume are inversely proportional.

Boyle's Law: P1 * V1 = P2 * V2

We are given the starting volume, and both pressures, so we can plug those numbers in.

(.428) * (2.5) = (.724) * (V2)

To solve for V2 first simplify:

1.07 = (.724) * V2

Then divide both sides by .724 to leave V2 behind

V2 = 1.478 (Rounded to 3 decimal places)

So the final volume is 1.478L

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Identify the Lewis acid and Lewis base from among the reactants in each of the following equations.
Alex

Answer:

Part A

Ag+ is the Lewis acid and NH3 is the Lewis base.

Part B

AlBr3 is the Lewis acid and NH3 is the Lewis base.

Part C

AlCl3 is the Lewis acid and Cl− is the Lewis base.

Explanation:

A Lewis acid is any specie that accepts a lone pair of electrons. Ag^+, AlBr3 and AlCl3 all accepted lone pairs of electrons according to the three chemical reaction equations shown. Hence, they are Lewis acids.

A Lewis base donates a lone pair of electrons. They include neutral molecules having lone pair of electrons such as NH3 or negative ions such as Cl- .

3 0
2 years ago
(Please Help)
Marianna [84]

Answer:

B

Explanation:

Trust me I've had problems like these

6 0
2 years ago
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What is the viscosity and flammability of refinery gas?
Liono4ka [1.6K]
Hydrocarbons

Hope this helps :)
6 0
3 years ago
Kerosene, a common space-heater fuel, is a mixture of hydrocarbons whose "average" formula is C₁₂H₂₆.
padilas [110]

The calculated enthalpy of formation of kerosene is 365.4 kJ and heat produced is 78650.3 kJ

For this, we need the normal enthalpy of formation given below

ΔH∘f(CO2)=−393.5kJ/molΔH∘f(H2O)\s=−241.8kJ/molΔH∘f(O2)=0kJ/mol

We shall now determine the enthalpy of kerosene formation:

H rxn = 24 mol H f (CO2) + 26 mol H f (H2O) + 2 mol H f (C12H26) + 37 mol H f (O2) + 1.50 104 kJ = 9444 kJ + 6286.8 kJ + 1500 kJ 2 mol H f (C12H26) = 730.8 kJ H f (C12H26) = 365.4 kJ

Kerosene has a density of 0.74 g/mL.

Kerosene volume (V) equals 0.63 gallons, or 0.63 x 3785.4, or 2384. 8 mL.

We shall now calculate the mass (m) of kerosene:

ρ=mVm\s=ρ×Vm\s=0.749g/mL×2384.mLm\s=1786.2g

We shall now discover the heat that 1786 generated.

Two grams of kerosene

Kerosene's molar mass is 170.33 g/mol.

The mass of two moles of kerosene is equal to 2*170.33*340.66g.

1.50104kJ of heat are generated by 340.66 g of kerosene.

1786 produced heat.

Kerosene 2 grams = 1.50 104 kJ 340.66 1786.2 g = 78650.3 kJ

Learn more about enthalpy here-

brainly.com/question/13996238

#SPJ4

5 0
1 year ago
1.How are volcanic soils important?
Paul [167]

Answer:

Soil provides nutrients, water, and minerals for plants and trees, stores carbon, and is home to billions of insects, small animals, bacteria, and many other microorganisms.

4 0
2 years ago
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