Answer:
The mass of iron piece = 586.84
Explanation:
Given,
Heat absorbed by iron piece(Q) = 5575 Joules.
specific heat capacity(Cp) = 0.95 J/g°C.
initial temperature(T₁) = 20.0°C
Final temperature(T₂) = 30.0°C
Mass of iron piece(m) = ?
The mass of iron piece can be calculated by using the formula
,
Q = (mass) (ΔT) (Cp)
Here, ΔT = T₂ - T₁ = 30°C - 20°C = 10°C
Substituting values we get,
5575 = (m)(10)(0.95)
Solving, we get,
m = 586.84 grams.
Therefore, mass of iron piece = 586.84 grams.
Answer : The partial pressure of B in the container is, 25.94 atm
Explanation : Given,
Total pressure = 38.9 atm
The given chemical reaction is:
Initial pressure p 0 0
At eqm. 0 2p p
The total pressure expression will be:
Total pressure = 2p + p
38.9 atm = 2p + p
38.9 atm = 3p
p = 12.97 atm
Now we have to calculate the partial pressure of B in the container.
The partial pressure of B in the container = 2p = 2(12.97) = 25.94 atm
Thus, the partial pressure of B in the container is, 25.94 atm
Answer:
Hg, Tl, Pb, Bi.
Explanation:
The elements that are all in the same period are: Hg, Tl, Pb, Bi.
Kindly, find the attached image that show that all elements are in period 6.
Rb, Sr, La, Zr
:
All are in period 5 except La is in period 6.
Al, Ga, Si, P
:
All are in period 3 except Ga is in period 4.
N, O, Cl, Br:
N, and O are in period 2. While Cl is in period 3 and Br is in period 4.
One is the plum pudding theory by Thomsons that theorized that positive and negative charges were randomly distributed in an atom. This was later discovered that the positive charge was located at the small nucleus center of the atoms and negative electrons on the outside.
Another is the aspect in Bohr model theory that electron orbit the nucleus like planets orbit the sun. Quantum mechanisms have come to disprove this and identify that electron orbit can only be predicted by probabilities and not in the certainty of their position around the nucleus of the atom. They randomly skip and hop (disappear and reappear) at positions around the nucleus.
Answer:
1 - producer, 2 - primary consumer, 3 - secondary consumer, 4 - tertiary consumer
Explanation: