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miv72 [106K]
3 years ago
7

Look back at your gizmo sheet on Activity B question number 3. The questions says, "How does a circuit with a 1.5-volt battery c

ompare to a circuit with a 9-volt battery?"
Choose the correct answer to the question. Think about what happened when you completed that part of the simulation.

Question 5 options:

Less current flows in the 1.5-volt circuit. The light bulbs are less bright.


More current flows in the 1.5-volt circuit. The light bulbs are brighter.
Chemistry
2 answers:
uranmaximum [27]3 years ago
8 0

Answer:

The answer is A Less current flows in the 1.5-volt circuit. The light bulbs are less bright.

Explanation:

I took the test

emmasim [6.3K]3 years ago
3 0

Answer:

Your answer will be A.

Explanation:

i promise its right good luck :)

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∆G° for the reaction of nitrogen with hydrogen to produce ammonia (see balanced chemical equation below) has a value of -33.3 kJ
Juliette [100K]

Answer:

-0.85KJ

Explanation:

Given N2(g) + H2(g) <--->2NH3(g)

Kp =[ P(NH3)]²/[P(H2)]³[P(N2)]

Where P is the pressure of the gas

P(H2)b= P(N2) = 125atm

P(NH3) = 200atm

Kp = 2²/(125)³(125)

Kp = 2.048 ×10^-6

∆G = -RTlnKp

R =0.008314 J/Kmol

T = 25 +273/= 298k

= 8.314 ×10^-3 × 298 × ln(2.048 ×10^-6)

= -0.008314 × 298 × (-13.099)

= 32.45KJ

∆G = ∆G° + RTlnKp

∆G = -33.3 + 32.45

∆G = -0.85KJ or -850J

3 0
4 years ago
Uranium-238 had a half life of 4.5 billion years. A 100 g sample of U-238 has decayed until only 25 g remain. How long did it ta
Natasha2012 [34]

awnseris chemical hhhh Explanation:

6 0
3 years ago
Why is bromine more electronegative than iodine?​
gavmur [86]

Answer

Accordingly the order of electronegativity of the given elements would be: Fluorine > Chlorine > Bromine > Iodine. ( Fluorine has the highest electronegativity.)

8 0
3 years ago
What percentage of 8 is 40?​
icang [17]

Answer:

gg

40%‰

Explanation:

3 0
3 years ago
4. Thorium-234 has a half-life of 24.1 days. What percentage of the original thorium-234 in a sample will remain after 144.6 day
kari74 [83]
How many half lives have elapsed?
actually the formula is like this
A=P(1/2)^(t/h)
P=iniital amount
t=time
h=half life
A=final amount
so

hmm, percent
so P=1 then
A=1(1/2)^(144.6/24.1)
A=1(1/2)^6
A=1/64
A=0.05625
so 5.625% is left
3 0
4 years ago
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