All categories

3 years ago

Can u Simplify this problem???!? 3t-7t+14t

2 answers:

7 0

Come on now, Tayala !

What if I say to you:
"Start with 3 cows, take away 7 cows, and then add 14 cows. How many are there ?"

Don't let the little 't' scare you. It doesn't matter one bit what 't' really is. It can be
a number, a teacher, a tiger, or a teacup. Whatever it is, you start with 3 of them,
take away 7 of them, and then add on 14 of them. How many are there ?

Hint: If there are not ten of them, then go back and look at the cows again.

MrRa [10]3 years ago

4 0

$3t-7t+14t=\\
\\
-4t+14t=10t$

You might be interested in

Find the derivative of cscx/3sinx

Neporo4naja [7]

$\frac{csc x}{3sinx} = \frac{1}{3sin ^{2}x }$

3 0

3 years ago

A reactangle has a perimeter 182 in and length 52 in . what is the width ?

Misha Larkins [42]

The Width Should Be 130 Because If You Subtract 182-52 You Get 130

4 0

4 years ago

Read 2 more answers

SOMEONE HELP ME AGAINNN LOL

olya-2409 [2.1K]

Answer:

open circle

Step-by-step explanation:

the open circle does not include the number. this is what you want because the solution is not equal to the number

7 0

3 years ago

Read 2 more answers

What are the intercepts of f(x)=5x-45

Mnenie [13.5K]

The y-intercept of f(x) = 5x - 45 would be -45, as that is what is represented in the equation. The way to find the x-intercept would be to solve the equation when f(x) = 0.

0 = 5x - 45
+ 45 + 45

45 = 5x
/5 /5
9 = x

And there we have it.
The intercepts of f(x) = 5x - 45 are as follows:

y-intercept = -45
x-intercept = 9

Hope that helped =)

7 0

3 years ago

The compressive strength of concrete is normally distributed with mu = 2500 psi and sigma = 50 psi. A random sample of n = 8 spe

Nata [24]

Answer:

$X \sim N(2500,50)$

Where $\mu=2500$ and $\sigma=50$

We select a sample size of n =8. Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$SE = \frac{50}{\sqrt{8}}= 17.678 psi$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

Let X the random variable that represent the compressive strength of concrete of a population, and for this case we know the distribution for X is given by:

$X \sim N(2500,50)$

Where $\mu=2500$ and $\sigma=50$

We select a sample size of n =8. Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$SE = \frac{50}{\sqrt{8}}= 17.678 psi$

7 0

3 years ago