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3 years ago

A helicopter’s speed increases from 30 m/s to 40 m/s in 5 seconds.

2 answers:

6 0

So, acceleration is the change of velocity in time. If no vectors are used, one can use speed:

a = (final speed - start peed)/ time = 10/5= 1 m/s^2,

Notice that the units are m/s^2, or (m/s)/s. That is speed (m/s) per unit time (s)

MariettaO [177]3 years ago

4 0

its 2 meters per sec

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The photon energies used in different types of medical x-ray imaging vary widely, depending upon the application. Single dental

pav-90 [236]

A) $5.0\cdot 10^{-11} m$

The energy of an x-ray photon used for single dental x-rays is

$E=25 keV = 25,000 eV \cdot (1.6\cdot 10^{-19} J/eV)=4\cdot 10^{-15} J$

The energy of a photon is related to its wavelength by the equation

$E=\frac{hc}{\lambda}$

where

$h=6.63\cdot 10^{-34}Js$ is the Planck constant

$c=3\cdot 10^8 m/s$ is the speed of light

$\lambda$ is the wavelength

Re-arranging the equation for the wavelength, we find

$\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4\cdot 10^{-15}J}=5.0\cdot 10^{-11} m$

B) $2.0\cdot 10^{-11} m$

The energy of an x-ray photon used in microtomography is 2.5 times greater than the energy of the photon used in part A), so its energy is

$E=2.5 \cdot (4\cdot 10^{-15}J)=1\cdot 10^{-14} J$

And so, by using the same formula we used in part A), we can calculate the corresponding wavelength:

$\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{1\cdot 10^{-14}J}=2.0\cdot 10^{-11} m$

4 0

3 years ago

The _____ period refers to the first two weeks of development after conception.

Mrac [35]

Answer: Geminal

Explanation:

5 0

3 years ago

Read 2 more answers

Andrea was watching her brother in the ocean and noticed that the waves were coming into the beach at a frequency of 0.777778 Hz

Stolb23 [73]

8 wave units I guess I tried it should be the answer though

3 0

3 years ago

What collides and creates a movement of heat called conduction?

Genrish500 [490]

Answer:

molecules

Explanation:

4 0

3 years ago

An experiment in your science class lists the materials needed for the lab. It is your job, as a lab partner, to measure out 25

andreyandreev [35.5K]

Overview:
You would use a graduated cylinder to measure 25 ml of the liquid and use a scale to weigh the amount of Magnesium (it can be a balance but most labs now have small scales) and you would carefully put small amounts of magnesium until it states 2.5 grams.

Procedure:
Take the graduated cylinder and place it on the table. Carefully take the water and fill the graduated cylinder up to 25ml. If you took to much just simply pour some out and if you didnt take enough then put more. After you measured the water then you can pour the 25 ml of water into a beaker, but this is totally optional.

For the magnesium first you put on the scale and set it to grams. Afterwards just take small pieces of the magnesium and place it on the scale until you reach 2.5 grams. Afterwards you can carefully place the magnesium in another beaker or something like that.

5 0

3 years ago