Given :
Initial velocity, u = -15 m/s.
Acceleration , a = 2 m/s².
Time taken to applied brake, t = 2.5 s.
To Find :
The velocity of the car at the end of the braking period.
How far has the car moved during the braking period.
Solution :
By equation :
Now, distance covered by car is :
Hence, this is the required solution.
According to the cameraman:
Initial velocity: 30 km/hr = 8.33 m/s
Final velocity: -(45 - 20) = -25 km/hr = -6.94 m/s²
a = (-6.94 - 8.33)/2
a = -7.64 m/s²
The direction is opposite to the motion of the car, that is, East.
According to the crew member on ground:
Initial velocity: 20 + 30 = 50 km/hr = 13.89 m/s
Final velocity: -45 km/hr = -12.5 m/s
a = (-12.5 - 13.89) / 2
a = -13.2 m/s²
The direction is the same, East.
Answer:
Explanation:
From the question we are told that
Mass of block
Radius of circle
Force of track
Normal Force on block
Generally the equation for Velocity of block is mathematically Given by the law of conservation of energy
For initial velocity
0.660 = 0.0425 x u^2/0.525 - 0.0425 x 9.8
Generally the equation for work done is mathematically Given by
The answer is C. Warm air is usually more humid than cold air. Hope this helps.