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3 years ago

Who is the featured character in an earth diver story

Physics

1 answer:

Irina-Kira [14]3 years ago

3 0

The featured character is the character who dives into water and brings up a small amount of mud or sand.

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What is the SPEED of a ball that travels 120 m in 6s?

AVprozaik [17]

Answer:

20m/second

Explanation:

The reason the answer is 20m/second is because to find the speed of the ball in this question you have to divide the distance over the time giving you the result of 20m/second

7 0

3 years ago

What is the density of a cube that has a mass of 3.75 g and a volume of 3 mL?

valina [46]

Answer:

$\displaystyle \rho=1.25\ g/ml$

Explanation:

Density

The density of a substance is the mass per unit volume. The density varies with temperature and pressure.

The formula to calculate the density of a substance of mass (m) and volume (V) is:

$\displaystyle \rho=\frac{m}{V}$

The cube has a mass of m=3.75 g and a volume of V=3 ml, thus the density is:

$\displaystyle \rho=\frac{3.75\ g}{3\ ml}$

$\boxed{\displaystyle \rho=1.25\ g/ml}$

Since 1 kg=1000 mg and 1 lt = 1000 ml, the density has the same value but with different units:

$\displaystyle \rho=1.25\ kg/l$

6 0

2 years ago

Calculate the heat, in kilocalories, that is absorbed if 183 g of ice at 0.0 ∘C is placed in an ice bag, melts, and warms to bod

boyakko [2]

Answer:

The total amount of heat needed will be $Q_T=21.411kcal$ .

Explanation:

We will divide the calculation in two: First, the heat needed to melt the ice, and then the heat needed to warm the resulting liquid from 0°C to 37°C.

$m=183g$

$l_f=80\frac{cal}{g} =334\frac{J}{g}$

$l_w=1\frac{cal}{g} =4.184\frac{J}{g}$

i) The fusion heat will be:

$Q_f=l_fm=14640cal=14.640kcal$

ii) The heat needed to warm the water from $T_i=0^{\circ}C$ to $T_i=37^{\circ}C$ will be:

$Q_w=l_wm(T_f-T_i)=6771cal=6.771kcal$

So, the total amount needed will be the sum of these two results:

$Q_T=Q_f+Q_w=14.640kcal+6.771kcal=21.411kcal$ .

8 0

3 years ago

A stone is thrown straight downward with a speed of 20 m/s from the top of a tall building. If the stone strikes the ground 3.0

Lady_Fox [76]

Do you remember this formula for the distance traveled while accelerated ?

Distance = (initial speed) x (t) plus (1/2) x (acceleration) x (t²)

I think this is exactly what we need for this problem.

initial speed = 20 m/s down
acceleration = 9.81 m/s² down
t = 3.0 seconds

Distance down = (20) x (3) plus (1/2) x (9.81) x (3)²

Distance = (60) plus (4.905) x (9)

Distance = (60) plus (44.145) = 104.145 meters

Choice D) is the closest one.

6 0

3 years ago

Sceiene question please show work for brainliest :)

Ad libitum [116K]

The answer to this questions would be nuclear engineer. The overall career of engineering would require physics as engineers need to know how the overall mechanics of nature affect the way their structure is built.

Hope this helped :D

5 0

4 years ago