I'm going to say 3 1\2. Let me know when you get the answer.
First of all to transfer <span>(2x - 1)(x + 6) = 0 into a form where we can plug it into the quadratic formula we need to use the FOIL method.
</span><span>(2x - 1)(x + 6) = 0
</span> becomes
2x*x+2x*6+-1*x+-1*6
which simplifies to
2x^2 + 12x - x - 6
and then we add like terms to get
2x^2 + 11x - <span>6
</span>
now that it is in the correct form we can identify "a" "b" and "c" by following this form
ax^2 + bx + c
looking back at the equation we got earlier
2x^2 + 11x - <span>6</span>
a=2,b=11,and c=-6
Divide: 7/3: 1/5= 7/3· 5/1= 7 · 5/3 · 1= 35/3
Answer:
The binomial: (x-2) (second option of the list) is a factor of the given trinomial
Step-by-step explanation:
You are looking for two binomial factors of the form; (x+a) and (x+b), with values "a" and "b" such that:
Their product "a times b" results in: "+14" (the numerical term in the initial trinomial 
,
and their combining "a+b" results in "-9" (the coefficient in the middle term of the trinomial)
Such number "a" and "b" are: "-2" and "-7".
We can see by multiplying the binomials formed with these numbers:
(x-2) and (x-7) that their product indeed renders the original trinomial:
therefore, the binomials (x-2) and (x-7) are factors of the given trinomial.
The only one shown among the four possible options is then: (x-2)
Assuming that you need to place the numbers on a number line;
1) Convert all numbers in one form, be it fraction or decimals
16/4 = 4
-2.7 = -2.7
1.75 = 1.75
1/5 = 0.2
2) Draw a number line with zero in the middle and positive numbers going to the right. The negative numbers go on left.
3) Place the decimal/fraction numbers into the number line, using a constant interval.
Hope I helped :)
