Okay let me walk you through this, a resistor resists right? its in the name. so you can guess that it would be 4th one down, because if you resist you don't stop, you just slow down. So you should definitely know current is energy, and since electrons is energy you know that current is the second one down. You already have two. Heres a good test taking strategy, the first one says "materials that do conduct electricity just not as well as conductors" so you know that something that conducts electricity well is a conductor, the third one down. now you have 3/5 and you haven't used any real knowledge. So now you are stuck between something that blocks electricity and something that is okay with it. Since you know a conductor does good, wouldnt a semi-conductor be the first one? since it is semi or partially a conductor. Then you are left with insulators to block them out. I hope I left a decent enough explanation. :)
Answer:
4-mid ocean ridge at divergent plate boundaries.
Answer:
a) T = 608.22 N
b) T = 608.22 N
c) T = 682.62 N
d) T = 533.82 N
Explanation:
Given that the mass of gymnast is m = 62.0 kg
Acceleration due to gravity is g = 9.81 m/s²
Thus; The weight of the gymnast is acting downwards and tension in the string acting upwards.
So;
To calculate the tension T in the rope if the gymnast hangs motionless on the rope; we have;
T = mg
= (62.0 kg)(9.81 m/s²)
= 608.22 N
When the gymnast climbs the rope at a constant rate tension in the string is
= (62.0 kg)(9.81 m/s²)
= 608.22 N
When the gymnast climbs up the rope with an upward acceleration of magnitude
a = 1.2 m/s²
the tension in the string is T - mg = ma (Since acceleration a is upwards)
T = ma + mg
= m (a + g )
= (62.0 kg)(9.81 m/s² + 1.2 m/s²)
= (62.0 kg) (11.01 m/s²)
= 682.62 N
When the gymnast climbs up the rope with an downward acceleration of magnitude
a = 1.2 m/s² the tension in the string is mg - T = ma (Since acceleration a is downwards)
T = mg - ma
= m (g - a )
= (62.0 kg)(9.81 m/s² - 1.2 m/s²)
= (62.0 kg)(8.61 m/s²)
= 533.82 N
