Answer:
Explanation:
a )
Reaction force of the ground
R = mg
= 160 N
Maximum friction force possible
= μ x R
= μ x 160
= .4 x 160
= 64 N .
b )
160 N will act at middle point . 740N will act at distance of 3 / 5 m from the wall ,
Taking moment about top point of ladder
160 x 1.5 + 740 x 3/5 + f x 4 = 900 x 3
240 + 444 + 4f = 2700
f = 504 N
c )
Let x be the required distance.
Taking moment about top point of ladder
160 x 1.5 + 740 x 3 x / 5 + .4 x 900 x 4 = 900 x 3 ( .4 x 900 is the maximum friction possible )
240 + 444 x + 1440 = 2700
x = 2.3 m
so man can go upto 2.3 at which maximum friction acts .
Answer:
Induced emf of the wire is 6.36 Volts.
Explanation:
It is given that,
Length of the wire, l = 75 cm = 0.75 m
Magnetic field, B = 0.53 T
Velocity, v = 16 m/s
The wire is moving straight up in the magnetic field. So, an emf is induced in the wire. It is given by :
So, the induced emf of the wire is 6.36 V. Hence, the correct option is (b) "6.36 V".
Answer:
1 ampere = 1 coulomb / sec = 1.6E19 electrons / sec
1 μamp = 1.0E-6 amperes
N = 60 μamp * 1.0E-6 amp / μamp * 1.6E19 electron / amp
N = 9.6E14 electrons
Answer:
Explanation:
Given:
- initial velocity of projectile,
- angle of projection above horizontal,
height of the initial projection point above the ground,
<u>Vertical component of the velocity:</u>
<u>The time taken in course of going up:</u>
(at top the final velocity will be zero)
<u>In course of going up the maximum height reached form the initial point:</u>
(at top height the final velocity is zero. )
using eq. of motion,
where:
final vertical velocity while going up.=0
maximum height
<u>Now the total height to be descended:</u>
Now the time taken to fall the gross height in course of falling from the top:
<u>Now the total time the projectile spends in the air:</u>
<u>Now the horizontal component of the initial velocity:</u>
(it remains constant throughout the motion)
Therefore the horizontal distance covered in the total time;