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ArbitrLikvidat [17]
2 years ago
11

Two polarizing sheets have their transmission axes crossed so that no light is transmitted. A third sheet is inserted so that it

s transmission axis makes an angle with the transmission axis of the first sheet. (a) Derive an expression for the intensity of the transmitted light as a function of (b) Show that the intensity transmitted through all three sheets is maximum when\
Physics
1 answer:
jek_recluse [69]2 years ago
5 0

Answer:

a)    I= I₀ (cos²θ - cos⁴θ)    b) 75.5º

Explanation:

a) For this exercise we must use Malus's law

         I = I₀ cos² θ

where tea is the angle between the two polarizers.

We apply this expression to our case

* Polarizer 1 suppose that it is vertical and polarizer 2 (intermediate) is at an angle θ with respect to the vertical

         I₁ = I₀ cos² θ

* We analyze for the polarity 2 and the last polarizer 3 which indicate that it must be at 90º from the first one, therefore it must be horizontal.

The angle of polarizers 2 and 3 is θ' measured from the horizontal, if we measure with respect to the vertical

              θ₂ = 90- θ’ = θ

fiate that in the exercise we must take a reference system and measure everything with respect to this system.

          I = I₁ cos² θ'

       

we substitute

         I = (I₀ cos² tea) cos² (θ - 90)

        cos (θ -90) = cos θ cos 90 + sin θ sin 90 = sin θ

         I = Io cos² θ sin² θ

        1= cos²θ+ sin²θ

       sin²θ = 1 - cos²θ

        I= I₀ (cos²θ - cos⁴θ)

b) to find when the intensity is maximum,

we can use that we have an extreme point when the drift is zero

          \frac{dI}{d \theta} = 0

          \frac{dI}{d \theta}= Io (2 cos θ - 4 cos³θ) = 0

whereby

            cos θ - 2 cos³ θ = 0

            cos θ ( 1 - 2 cos² θ) = 0  

The zeros of this function are in

           θ = 90º

           1-2cos²θ =0       cos θ = 0.25  θ =  75.5º

Let's analyze this two results for the angle of 90º the intnesidd is zero with respect to the first polarizer, so it is not an acceptable solution.

Consequently, the angle that allows the maximum intensity to pass is 75.5º

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wel

Answer:

Distance = 16.9 m

Explanation:

We are given;

Power; P = 70 W

Intensity; I = 0.0195 W/m²

Now, for a spherical sound wave, the intensity in the radial direction is expressed as a function of distance r from the center of the sphere and is given by the expression;

I = Power/Unit area = P/(4πr²)

where;

P is the sound power

r is the distance.

Thus;

Making r the subject, we have;

r² = P/4πI

r = √(P/4πI)

r = √(70/(4π*0.0195))

r = √285.6627

r = 16.9 m

8 0
3 years ago
Select the correct answer.
MariettaO [177]

Answer:

can't explain but is correct

7 0
3 years ago
The height of a helicopter above the ground is given by h = 3.15t3, where h is in meters and t is in seconds. At t = 2.10 s, the
alexandr1967 [171]

Answer:

The mailbag will take 2.44 seconds to reach the ground.

Explanation:

The height of a helicopter above the ground is given by:

h = 3.15\times t^3

Height of helicopter at t = 2.10 seconds

h(2.10 )=3.15\times (2.10 )^3 m=29.17 m

The helicopter releases a small mailbag from the height of 29.17 m.

The initial velocity of mailbag = u = 0 m/s

Duration in which mailbag will reach the ground = T

Acceleration due to gravity = g = 9.8 m/s^2

Using second equation of motion ;

s=ut+\frac{1}{2}gt^2

We have , s = 29.17

u = 0 m/s

t = T

29.17m=0 m/s\times T+\frac{9.8 m/s^2\times T^2}{2}

Solving for T, we gte :

T = 2.44 seconds

The mailbag will take 2.44 seconds to reach the ground.

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3 years ago
The distance covered by a car moving with a speed of 36 km/h in 15m is (a) 0.9 km (b) 9.0 km (C) 90 km (d) 900 km​
GuDViN [60]

This is a uniform rectilinear motion exercise.

To start solving this exercise, we obtain the following data:

<h3>Data:</h3>
  • v = 36 km/h
  • d = ¿?
  • t = 15 min = 0.25 hr

                                     Minutes to hour converter

                                                  60 min = 1 hour

                                       \boldsymbol{\sf15\not{min}*\dfrac{1 \ hr}{60 \not{min}}=0.25 \ hr  }}

To calculate distance, speed is multiplied by time.

We apply the following formula: d = v * t

We substitute our data into the formula:

                                     \boldsymbol{\sf{d=v*t}}

                                     \boldsymbol{\sf{d=36 \dfrac{km}{\not{h}}*0.25 \not{h} }}

                                     \boldsymbol{\sf{d=9 \ km}}

The distance traveled by a car moving with a speed of 36 km/h in 15 m is 9 km.

  • Therefore, the correct option is "B".
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Schach [20]

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