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d1i1m1o1n [39]
3 years ago
12

Who is good with sequences.

Mathematics
2 answers:
hjlf3 years ago
6 0
I'm usually pretty good at them. :)
slava [35]3 years ago
5 0
After reading this question there is not much to gather from it. But in my personal experience from what I know problem solvers are good with sequences. I am good with basic sequences but when it comes to algebra thats above my pay grade.
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g(x)= 2|x+3|-3

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(-2,-5)(-3,-6) slope
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Answer: Slope = 1

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Express XCVI to Hindu Arabic<br>numerals.​
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3 years ago
Suppose that 50% of all babies born in a particular hospital are boys. If 6 babies born in the hospital are randomly selected, w
WINSTONCH [101]

Using the binomial distribution, it is found that there is a 0.3438 = 34.38% probability that fewer than 3 of them are boys.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem, the values of the parameters are given as follows:

n = 6, p = 0.5.

The probability that fewer than 3 of them are boys is given by:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.5)^{0}.(0.5)^{6} = 0.0156

P(X = 1) = C_{6,1}.(0.5)^{1}.(0.5)^{5} = 0.0938

P(X = 2) = C_{6,2}.(0.5)^{2}.(0.5)^{4} = 0.2344

Then:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0156 + 0.0938 + 0.2344 = 0.3438

0.3438 = 34.38% probability that fewer than 3 of them are boys.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

7 0
2 years ago
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