The ball travels 18.3 m at a speed of 35.6 m/s.
How long does the trip take ?
time = (distance)/(speed) = (18.3 m) / (35.6 m/s) = 0.514 second
All during the trip, the ball is spinning at the rate of 29 rev/second.
Spinning at 29 rev/s for 0.514 sec, it completes 14.91 revolutions,
before stopping with a THUNK in the pocket of the catcher's mitt.
Answer:
The objects were 1.8m apart.
Explanation:
We will start stating the Coulomb's Law. It says that:
Where F_e is the electric force between the objects, q_1 and q_2 are the magnitude of the charge of the objects, r is the distance between them and K is the Coulomb's constant (
in vacuum). Solving for the distance r we have:
Plugging the given values into this equation, we obtain:
In words, the two charged objects were 1.8m apart.
B. velocity is the speed in any given direction.
It relates because<span> the </span>energy<span> of an object to its </span>mass and since fission requires energy to do so, e=mc^2 relates to it.
WHEN AUTO MOBILE MAKERS SAY THAT THEIR CARS ARE MORE POWERFUL IT MEANS AS IN TORQUE
