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Grace [21]
3 years ago
15

2. Why is it safer for a car to deform when it crashes into another car?

Physics
2 answers:
shepuryov [24]3 years ago
8 0

Answer:

Less impact???

Explanation:

erastovalidia [21]3 years ago
6 0

Answer:

Crumple zones work by managing crash energy and increasing the time over which the deceleration of the occupants of the vehicle occurs. Also preventing intrusion into or deformation of the passenger/passenger seat.

**brainly please

Explanation:

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Tom is going to your left at 90% of the speed of light and Joan is going to your right at 90% of the speed of light. What will T
MrMuchimi

Answer:

You are moving away from him at 90% the speed of light. Joan is moving away from him at as speed that is faster than 90% of the speed of light but slower than the whole speed of light.

Explanation:

According to relativity, you cannot exceed the speed of light.

8 0
4 years ago
Sam is observing the velocity of a car at different times. After three hours, the velocity of the car is 53 km/h. After six hour
Serhud [2]
For the answer to the question above, first find out the gradient. 

<span>m = rise/run </span>
<span>=(y2-y1)/(x2-x1) </span>

<span>the x's and y's are the points given: "After three hours, the velocity of the car is 53 km/h. After six hours, the velocity of the car is 62 km/h" </span>
<span>(x1,y1) = (3,53) </span>
<span>(x2,y2) = (6,62) </span>

<span>sub values back into the equation </span>
<span>m = (62-53)/(6-3) </span>
<span>m = 9/3 </span>
<span>m = 3 </span>

<span>now we use a point-slope form to find the the standard form </span>
<span>y-y1 = m(x-x1) </span>
<span>where x1 and y1 are any set of point given </span>
<span>y-53 = 3(x-3) </span>
<span>y-53 = 3x - 9 </span>
<span>y = 3x - 9 + 53 </span>
<span>y = 3x + 44 </span>

<span>y is the velocity of the car, x is the time.
</span>I hope this helps.
4 0
3 years ago
when hard stabilization structures such as groins are used to stabilize a shoreline, the change in the longshore current results
Nikitich [7]

When hard stabilization structures such as groins are used to stabilize a shoreline, the change in the longshore current results <u>deposition of sediment. </u>

On the upcurrent side of the barrier, sediment is deposited as the longshore current slows.

What is Hard stabilization?

  • Hard stabilization is the prevention of erosion through the use of artificial barriers.
  • Other hard stabilization structures, such as breakwaters and seawalls, are built parallel to the beach to protect the coast from the force of waves.
  • Hard stabilization structures, such as groins, are built at right angles to the shore to prevent the movement of sand down the coast and maintain the beach.
  • These constructions are made to last for many years, but because they detract from the visual splendor of the beach, they are not always the ideal answer.
  • Additionally, they affect the habitats and breeding sites of native shoreline species, interfering with the ecosystem's natural processes.

Learn more about the Hard stabilization with the help of the given link:

brainly.com/question/16022736

#SPJ4

4 0
2 years ago
A cyclist has a constant speed of 12 m/s. What is the magnitude of the displacement of the cyclist after 18 seconds?
Katyanochek1 [597]

Answer:

216 m

Explanation:

Assuming a straight line:

Δx = vt

Δx = (12 m/s) (18 s)

Δx = 216 m

7 0
3 years ago
Please Hurry<br> Find the magnitude and direction of these two vectors
daser333 [38]

Answer:

11.79 m

Explanation:

Break into horiz and vert components then add them....then use Pythag theorem for magnitude

(B is at angle 250° )

Horiz :   7.7 cos 27.8   + 16.3 cos 250 = 1.236 m

Vert  :    7.7 sin 27.8    + 16.3  sin 250 = -11.73

Mag^2 = 1.236^2 + (-11.73)^2  

   Magnitude = 11.79 m

Direction = arctan ( -11.73/1.236) = - 84°    ( = 276°)

8 0
2 years ago
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