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Nastasia [14]
3 years ago
9

A woman throws a baseball from the back of an airplane to the front. From the perspective of the woman, the baseball travels at

an average speed of 20 m/s. To an observer on the ground, the airplane is traveling at a constant speed of 820 km/h. What is the speed of the baseball from the perspective of the ground observer?
Physics
1 answer:
andre [41]3 years ago
8 0

So for these questions, you add if they're going in the same direction and you subtract if it's in the opposite direction for the ground observer, since the ball is moving in the opposite direction of the plane, it would be 820 km/h - 15 m/s 15 m/s * 60 s/min * 60 min/hour = 54000 m/h, 54000 m/h * 1000 m/km = 54 km/h 820 km/h - 54 km/h = 768 km/h to the ground observer By the way, I don't think it's safe for someone to throw a baseball that fast in an airplan

25. It's travelling at constant speed so acceleration is 0 
d = v * t 
t = d / v 
t = 732 000 / 327 
t= 2238.5 secs = 37.31 minutes 

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A pendulum built from a steel sphere with radius r cm 5 and density stl kg m S 3 7800 is attached to an aluminum bar with length
Ad libitum [116K]

Answer:

a)  I = 0.0198 kg m² ,  b)    I = 21.85 kg m²

Explanation:

For this exercise we will use the definition of moment of inertia

        I = ∫ r² dm

For body with high symmetry they are tabulated

sphere  I = 2/5 m r²

bar with respect to  center of mass I = 1/12 m L²

let's calculate the mass of each body

bar

        ρ = m / V

        m = ρ V

        m = ρ l w h

where we are given the density of the bar rho = 32840 kg / m³ and its dimensions 1 m, 0.8 cm and 4 cm

        m = 32820 1 0.008 0.04

        m = 10.5 kg

Sphere

       M = ρ V

       V = 4/3 pi r³

       M = rgo 4/3 π r³

give us the density 37800 kg / m³ and the radius of 5 cm

       M = 37800 4/3 π 0.05³

       M = 19.8 kg

a) asks us for the moment of inertia of the sphere with respect to its center of mass

        I = 2/5 M r²

        I = 2/5 19.8 0.05²

        I = 0.0198 kg m²

b) the moment of inertia with respect to the turning point, for this we will use the theorem of parallel axes

        I = I_cm + M d2

where d is the distance from the body to the point of interest

        I_cm = 0.0198 kg m²

the distance to the pivot point is

        l = length of the bar + radius of the sphere

        l = 1 + 0.05 = 1.005 m

        I = 0.0198 + 19.8 1.05²

        I = 21.85 kg m²

8 0
3 years ago
Cara is swimming in a river. She can swim downstream up to a maximum speed of 66 meters per-minute. If she is swimming downstrea
makvit [3.9K]
It would be 429 because in the question it said “ if she was swimming downstream of HALF of her maximum speed, how far will she swim for 13 minutes” so first you would divide 66 by 2 and get 33 then you would multiply 33 by 13 to get you’re answer.
8 0
3 years ago
Read 2 more answers
4) Explain which electric charges attract and which electric charges repel (push away)
DaniilM [7]

Explanation:

According to the fundamental law of electrostatics, like charges which are ( only positive or only negative charges) repel while unlike charges which are ( positive and negative charges ) attract each other.

that is: ( +++++ ++++++) they repel

while ( +++++++ ———) they attract

7 0
3 years ago
HI PLEASE HELP!
butalik [34]

Answer:

Chemical reactions occur slower at lower temperatures and faster at higher temperatures. When you put a glow stick in cold water, the chemical reaction slows down but will last for a longer period of time. When you put a glow stick in hot water, the reaction speeds up but will be over quicker.

Explanation:

(self-explanatory)

I hope this helps, have a nice day.

7 0
3 years ago
A 10kg box is sliding at 50m/s. Find the momentum
MAXImum [283]

Answer:

The momentum of the ball is 500 kg·m/s

Explanation:

The momentum is given by Mass × Velocity

The given parameters are;

The mass of the box = 10 kg

The velocity by which the box is sliding = 50 m/s

Therefore, the momentum of the ball is given as follows;

The momentum of the ball = 10 kg × 50 m/s = 500 kg·m/s

The momentum of the ball = 500 kg·m/s

5 0
3 years ago
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