Answer:
Explanation:
Initial kinetic energy of the system = 1/2 mA v0²
If Vf be the final velocity of both the carts
applying conservation of momentum
final velocity
Vf = mAvo / ( mA +mB)
kinetic energy ( final ) = 1/2 (mA +mB)mA²vo² / ( mA +mB)²
= mA²vo² / 2( mA +mB)
Given 1/2 mA v0² / mA²vo² / 2( mA +mB) = 6
mA v0² x ( mA +mB) / mA²vo² = 6
( mA +mB) / mA = 6
mA + mB = 6 mA
5 mA = mB
mB / mA = 5 .
The question is missing, however, I guess the problem is asking for the value of the force acting between the two balls.
The Coulomb force between the two balls is:

where

is the Coulomb's constant,

is the intensity of the two charges, and

is the distance between them.
Substituting these numbers into the equation, we get

The force is repulsive, because the charges have same sign and so they repel each other.
In the question where as a model rocket is launched straight upward with an initial speed of 50.0m/s and it accelerate with a constant acceleration of 2m/s^2 until it engines stop at an altitude od 150. So the following are the answer to your question:
a.The motion, the acceleration was equals to Zero
b.the maximum height is 150m
Power = voltage x current
12v x 50A = 600 watts
Answer:
A. 8.175 N
B. 49.05 N
Explanation:
A.
Acceleration due to gravity (moon) = 1/6 * (acceleration due to gravity (earth)
Acceleration due to gravity (earth) = 9.81 m/s2
Acceleration due to gravity (moon) = 9.81/6
= 1.635 m/s
Weight. Fm = acceleration due to gravity * mass
= 1.635 * 5
= 8.175 N
B. Acceleration due to gravity (earth) * mass = Fe
= 9.81 * 5
= 49.05 N