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Liono4ka [1.6K]
3 years ago
10

A painter uses 1.2 liters of the paint to cover 1m2 of the wall. How much paint will he need to cover 0.5m2? 30 points!

Mathematics
1 answer:
loris [4]3 years ago
6 0

Answer:

0.6 liters

Step-by-step explanation:

Half the area is expected to take half the paint.

... (0.5 m²)/(1 m²) × (1.2 L) = 0.5×1.2 L = 0.6 L

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Answer:

  see below

Step-by-step explanation:

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3 0
3 years ago
EXTRA POINTS * how do you graph y=2x + 1
ahrayia [7]

Step-by-step explanation:

first u need to pick a random coordinate to substitute the X . example 0

y = 2(0) + 1

y =1 , X= 0

X= 1

y= 2(1) + 1

y= 3, X= 1

then you continue this same process and again until u have at least two points to draw a straight line. it kinda depended if u want to fill the entire graph.

3 0
4 years ago
Which is the factorization of 8x^2+13-6
QveST [7]
(8x+3)(x-2)


Explanation

8x^2-13x-6
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3 0
3 years ago
3x-y=1;d:{-3,-1,0,4}
Maslowich
First, rearrange the equation so that it is solving for y:
3x - y = 1
     +y   +y
3x = y + 1
-1         -1
3x - 1 = y
Now substitute the domain values you have listed into the 'x' of the equation to get the values for y.
For example:
3(-3) - 1 = y
-9 - 1 = y
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8 0
3 years ago
Fifty-three percent of employees make judgements about their co-workers based on the cleanliness of their desk. You randomly sel
GarryVolchara [31]

Answer:

The unusual X values ​​for this model are: X = 0, 1, 2, 7, 8

Step-by-step explanation:

A binomial random variable X represents the number of successes obtained in a repetition of n Bernoulli-type trials with probability of success p. In this particular case, n = 8, and p = 0.53, therefore, the model is {8 \choose x} (0.53) ^ {x} (0.47)^{(8-x)}. So, you have:

P (X = 0) = {8 \choose 0} (0.53) ^ {0} (0.47) ^ {8} = 0.0024

P (X = 1) = {8 \choose 1} (0.53) ^ {1} (0.47) ^ {7} = 0.0215

P (X = 2) = {8 \choose 2} (0.53)^2 (0.47)^6 = 0.0848

P (X = 3) = {8 \choose 3} (0.53) ^ {3} (0.47)^5 = 0.1912

P (X = 4) = {8 \choose 4} (0.53) ^ {4} (0.47)^4} = 0.2695

P (X = 5) = {8 \choose 5} (0.53) ^ {5} (0.47)^3 = 0.2431

P (X = 6) = {8 \choose 6} (0.53) ^ {6} (0.47)^2 = 0.1371

P (X = 7) = {8 \choose 7} (0.53) ^ {7} (0.47)^ {1} = 0.0442

P (X = 8) = {8 \choose 8} (0.53)^{8} (0.47)^{0} = 0.0062

The unusual X values ​​for this model are: X = 0, 1, 7, 8

6 0
4 years ago
Read 2 more answers
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