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3 years ago

Why is Sunlight a composite light

Physics

1 answer:

STatiana [176]3 years ago

3 0

The Sun *emits* white light, which is actually a composite of all of the visible frequencies of light.

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An Airbus A380 airliner can takeoff when its speed reaches 80 m/s. Suppose its engines together can produce an acceleration of 3

Tomtit [17]

Answer:

(a). The time is 26.67 sec.

(b). The distance traveled during this period is 1066.9 m.

Explanation:

Given that,

Speed = 80 m/s

Acceleration = 3 m/s

Initial velocity = 0

(a). We need to calculate the time

Using equation of motion

$v = u+at$

$t = \dfrac{v-u}{a}$

Put the value into the formula

$t = \dfrac{80-0}{3}$

$t =26.67\ sec$

The time is 26.67 sec.

(b). We need to calculate the distance traveled during this period

Using equation of motion

$s = ut+\dfrac{1}{2}at^2$

$s = 0+\dfrac{1}{2}\times3\times(26.67)^2$

$s =1066.9\ m$

The distance traveled during this period is 1066.9 m.

Hence, This is the required solution.

7 0

3 years ago

PLEASE HELP!!!!!

Sunny_sXe [5.5K]

I need to force in order to answer. What is it

3 0

3 years ago

a sailboat sails 50 km to the north then 80 km in the direction 38 degrees west of south. what is the net displacement of the bo

True [87]

Answer:

35.489km

Explanation:

a diagram illustrating the question is attached

now, applying cosine rule to find the displacement c

cosine rule;

c²=a²+b²-2abCos ∅

c²=50²+80²-2(50)(80)Cos 38°

c²=2500 + 6400 - (8000×0.9951)

c²=8900-7640.589

c²=1259.411

c= $\sqrt{1259.411}$

c=35.49km

8 0

4 years ago

Read 2 more answers

A sample contains radioactive atoms of two types, A and B. Initially there are five times as many A atoms as there are B atoms.

victus00 [196]

Answer:

Explanation:

Initially no of atoms of A = N₀(A)

Initially no of atoms of B = N₀(B)

5 X N₀(A) = N₀(B)

N = N₀ $e^{-\lambda t}$

N is no of atoms after time t , λ is decay constant and t is time .

For A

N(A) = N(A)₀ $e^{-\lambda_1 t}$

For B

N(B) = N(B)₀ $e^{-\lambda_2 t}$

N(A) = N(B) , for t = 2 h

N(A)₀ $e^{-\lambda_1 t}$ = N(B)₀ $e^{-\lambda_2 t}$

N(A)₀ $e^{-\lambda_1 t}$ = 5 x N₀(A) $e^{-\lambda_2 t}$

$e^{-\lambda_1 t}$ = 5 $e^{-\lambda_2 t}$

$e^{\lambda_2 t}$ = 5 $e^{\lambda_1 t}$

half life = .693 / λ

For A

.77 = .693 / λ₁

λ₁ = .9 h⁻¹

$e^{\lambda_2 t}$ = 5 $e^{\lambda_1 t}$

Putting t = 2 h , λ₁ = .9 h⁻¹

$e^{\lambda_2\times 2}$ = 5 $e^{.9\times 2}$

$e^{\lambda_2\times 2}$ = 30.25

2 x λ₂ = 3.41

λ₂ = 1.7047

Half life of B = .693 / 1.7047

= .4065 hours .

= .41 hours .

6 0

3 years ago

A truck moves 60 km West, and then 80 km North, and then

stira [4]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Distance travelled by the truck is ~

$\boxed{240 \: \: km}$

And it's displacement is ~

$\boxed{0 \: \: km}$

$\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}$

See the diagram in attachment for reference ~

Let O be the initial point, It travels 60 km towards west till point B and then 80 km towards north till point P and returns to initial point O in a straight line, now as we can observe here, it forms a right angled Triangle.

The measure of two legs is 60 km and 80 km, let's find the hypotenuse ~

According to Pythagoras theorem ~

hypotenuse² = sum of squares of other two legs

that is ~

$h {}^{2} = 60 {}^{2} + 80 {}^{2}$

${h}^{2} = 3600 + 640 0$

$h {}^{2} = 10000$

$h = \sqrt{10000}$

$h = \sqrt{100 \times 100}{}$

$h = 100 \: \: km$

So, the distance between the point A and O is 100 km

Now, The total distance is equal to the distance covered through actual path that is ~

60 km + 80 km + 100 km

240 km

And displacement is the distance between the final point and initial point, but since the truck returns to the point from where it started the journey, so the final and initial point is same therefore displacement is equal to 0.

4 0

3 years ago