What is the net force needed to accelerate a 5 kg object at 3 m/s2? Suppose that in this situation you discovered that there is
1 answer:
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Explanation:
Given that,
Force,
The particle displaces from (1,2,-3) m to (2,5,-1) m.
We need to find the work done by the force. Work done by the force is given by :
W = Fd
It is equal to the dot product of force and displacement.
Displacement from (1,2,-3) m to (2,5,-1) m is (2-1, 5-2, -1-(-3)) or (1, 3, 2) m
Work done,
We know that, i.i=j.j=k.k=1
So,
So, the work done by the force is 1 J.
Answer:
The astronaut's acceleration is 155.1 times the vehicle's acceleration
Explanation:
These effects due to Newton's third law of action and reaction. Since the forces are equal but in the opposite direction and each acting on a different body. We distance that the Force is F let's calculate the acceleration of the vehicle and the astronaut
Astronaut
F = a₁
Vehicle
F = a₁
F = 555.1 a₂
Let's match the equation
a₁ = 155.1
a₂
a₁ = 155.1 a₂
a₁ / a₂ = 155.1
The astronaut's acceleration is 155.1 times the vehicle's acceleration
We see that even when the acceleration of the vehicle is small, there is a very high multiplicative factor.
One method to improve this situation is that the vehicles fear some small retro-rocket vehicles to reduce their acceleration. This would have a very favorable impact on the astronaut's mission.
Another method would be for the astronaut himself to have the retro-rocket and control his acceleration.