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VashaNatasha [74]
2 years ago
13

What is the difference between radial acceleration and tangential acceleration and how do you calculate both of these accelerati

ons?
Physics
1 answer:
sergey [27]2 years ago
8 0

Answer:

Tangential acceleration is in the direction of velocity - along the circumference of a circle if the object is undergoing circular motion

a = (V2 - V1) / T

Radial acceleration is perpendicular to the direction of motion if the object is not moving in a straight line (perhaps along the circumference of a circle)

a = m V^2 / R = m ω^2 R   where R is the radius vector of the velocity - note that the Radius vector is directed from the center of motion to the object and for circular motion would be constant in magnitude but not  in direction

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A horizontal force of 400 N is exerted on a 2.0-kg ball as it rotates (at
frutty [35]

Answer:

the speed of the ball is 10 m/s

Explanation:

Given;

magnitude of exerted force, F = 400 N

mass of the ball, m = 2 kg

radius of the circle, r = 0.5

The speed of the ball is calculated by applying centripetal force formula;

F = \frac{mv^2}{r} \\\\v^2 = \frac{Fr}{m}\\\\v = \sqrt{\frac{Fr}{m}}\\\\ v = \sqrt{\frac{400*0.5}{2}}\\\\v = 10 \ m/s

Therefore, the speed of the ball is 10 m/s

6 0
3 years ago
Read 2 more answers
A tennis player swings her 1000 g racket with a speed of 11 m/s. She hits a 60 g tennis ball that was approaching her at a speed
shusha [124]

Answer:

- 3.72 Ns.

9.44 m/s

Explanation:

mass of racket, M = 1000 g = 1 kg

mass of ball, m = 60 g = 0.06 kg

initial velocity of racket, U = 11 m/s

initial velocity of ball, u = 18 m/s

final velocity of ball, v = - 44 m/s

Let the final velocity of the racket is V.

(a) Momentum is defined as the product of mass and velocity of the ball.

initial momentum of the ball = m x u = 0.06 x 18 = 1.08 Ns

Final momentum of the ball = m x v = 0.06 x (- 44) = - 2.64 Ns

Change in momentum of the ball = final momentum - initial momentum

                                                        = - 2.64 - 1.08 = - 3.72 Ns

Thus, the change in momentum of the ball is - 3.72 Ns.

(b) By use of conservation of momentum

initial momentum of racket and ball = final momentum of racket and ball

1 x 11 + 0.06 x 18 =  1 x V - 0.06 x 44

12.08 = V - 2.64

V = 9.44 m/s

Thus, the final velocity of the racket afetr the impact is 9.44 m/s .

3 0
3 years ago
A can of soup is begin heated in a sauce pan. as the soup is heated, the warm fluid becomes less dense and rises, while the cool
Alexxandr [17]
It is c convection because convection is when something is hot therefore less dense material to rise and cooler material to sink under the influence of gravity
8 0
3 years ago
Which bond(s) shown are double bonds?
Nikitich [7]

Answer:

I'm pretty sure its the 2nd one.

3 0
3 years ago
While standing on the edge of the grand canyon, you see a rattlesnake and scream. You hear the echo of the scream off canyon flo
bezimeni [28]

Answer:

1904 m

Explanation:

\pink{\frak{Given}}\begin{cases} \textsf{ You scream after seeing a rattle snake  .}\\\textsf{Scream is heard after 11.2 s .} \end{cases}

Here we need to find out the depth of the canyon . When you will scream after seeing a snake , the sound produced will travel till the end of the canyon and after hitting the end , it will travel back to you .

  • So if the depth of the canyon is d (say) , then the total distance travelled by the sound wave will be d + d = 2d .

And we know that the speed of the sound is approximately 340m/s in air , so we can use the formula distance = speed * time to calculate the depth of the canyon . So ,

\sf \longrightarrow Distance = (Speed)(Time) \\

\sf \longrightarrow 2d = 340m/s * 11.2 s\\

\sf \longrightarrow d = \dfrac{340m/s * 11.2s}{2} \\

\sf \longrightarrow \boxed{\bf Depth_{canyon}= 1904m }\\

6 0
2 years ago
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