Answer:
ΔU° = 56.0 J
Explanation:
Step 1: Given data
- Work done to compress the gas (w): 83.0 J (When work is done on the gas, w is positive).
- Heat given off to the surroundings (q): -27.0 J (When heat is released to the surroundings, q is negative)
Step 2: Calculate the change in the internal energy of the gas (ΔU°)
The internal energy of a gas is the energy contained within it. We can calculate it using the following expression.
ΔU° = q + w
ΔU° = -27.0 J + 83.0 J
ΔU° = 56.0 J
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The balanced equation for the above reaction is as follows;
3NO₂ + H₂O --> 2HNO₃ + NO
stoichiometry of NO₂ to NO is 3:1
molar volume is where 1 mol of any gas occupies a volume of 22.4 L
volume of gas is directly proportional to number of moles of gas.
therefore stoichiometry can be applied for volume as well.
volume ratio of NO₂ to NO is 3:1
volume of NO₂ reacted - 854 L
therefore volume of NO formed - 854 L /3 = 285 L
volume of NO formed - 285 L
Answer:
n = 4, l = 2
Explanation:
The number 4 in 4d is the principal quantum number (n).
The letter d in 4d tells us that we have a d orbital, as determined by the <em>secondary quantum number (l</em>).
The quantum number l tells us the shape of the orbital.
l = 0 s orbital
l = 1 p orbital
l = 2 d orbital
