Well for one the Oceans food chain starts with the sun and then microscopic organisms such as phytoplankton, and if they were destroyed the fish and other small creatures would eventually die off and then larger animals would too. Then that could lead to not much sea life, or sea food left for other people and animals
Answer:
- 2K(s) + (1/8) S₈ (s) + (3/2) O₂(g) → K₂SO₃ (s)
Explanation:
The<em> standard enthalpy of formation </em>of a substance is the change in enthalpy that happens when one mole of the substance is formed from the elements in their standard states.
Thus, to calculate the standard state of formation of a compound you must:
- 1. Identify the elements that form the compound
- 2. Identify the standard form of each element
- 3. Set the equation to form one mole of the compound, which may require to use fractional coefficients for some of the elements.
Applying that to our compound K₂SO₃
<u>1. Elements:</u>
- potassium, K;
- sulfur, S; and
- oxygen, O.
<u />
<u>2. Standard forms of the elements:</u>
- potassium: solid, K(s)
- sulfur: solid, octatomic molecules, S₈ (s)
- oxygen: diatomic gas, O₂(g)
<u>3. Reaction:</u>
- K(s) + S₈ (s) + O₂(g) → K₂SO₃ (s)
Balance, keeping one mole of K₂SO₃. You will need to use fractional coefficients for some elements:
- 2K(s) + (1/8) S₈ (s) + (3/2) O₂(g) → K₂SO₃ (s) ← answer
Examples of carbohydrates: <span><span>glucose (monosaccharide) and </span><span>fructose (monosaccharide)
Examples of lipids: fats and steroids
Source credit:
</span></span>http://examples.yourdictionary.com/examples-of-lipids.html
https://www.thoughtco.com/examples-of-carbohydrates-603884
Based on the dilution formula, 0.1 mL of the stock solution of the enzyme is required to prepare a 50-fold diluted enzyme in 0.01 M HCl.
<h3>How can 50-fold dilution of the enzyme be done?</h3>
The 50-fold dilution of the stock enzyme solution can be done by using the dilution formula to determine the given volume of the stock solution required.
The dilution formula is given below:
where:
- C1 = Initial concentration of enzyme
- C2 = Final concentration of enzyme
- V1 = Initial volume
- V2 = Final volume
From the given data for the enzyme dilution;
C1 = 1
C2 = 1/50 = 0.02
V1 = x
V2 = 5 ml
Making V1 subject of formula in the dilution formula:
V1 = C2V2/C1
V1 = 0.02 * 5/1 = 0.1 mL
Therefore, 0.1 mL of the stock solution of the enzyme is required to prepare a 50-fold diluted enzyme in 0.01 M HCl.
Learn more about dilution at: brainly.com/question/24709069
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