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DaniilM [7]
2 years ago
15

What role does the wire play in voltaic cell

Chemistry
1 answer:
VashaNatasha [74]2 years ago
8 0
It allows electrons to flow from the anode to the cathode.
You might be interested in
What mass of silver oxide, Ag2O is required to produce 25.0 g of silver sulfadiazine, AgC10H9N4SO2, from the reaction of silver
Wittaler [7]

Answer:

8.1107 g

Explanation:

The given reaction:

2C_{10}H_{10}N_4SO_2+Ag_2O\rightarrow 2AgC_{10}H_9N_4SO_2+H_2O

Given that:

Mass of silver sulfadiazine = 25.0 g

Molar mass of silver sulfadiazine = 357.14 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{25.0\ g}{357.14\ g/mol}

Moles= 0.07\ mol

From the reaction,

2 moles of silver sulfadiazine are formed from 1 mole of silver oxide

So,

1 mole of silver sulfadiazine are formed from 1/2 mole of silver oxide

0.07 mole of silver sulfadiazine are formed from 1/2*0.07 mole of silver oxide

Moles of silver oxide = 0.035 moles

Molar mass  of silver oxide = 231.735 g/mol

Mass = Moles * Molar mass = 0.035 moles * 231.735 g/mol = 8.1107 g

4 0
3 years ago
What are the intermolecular forces of Sulfate ion
Salsk061 [2.6K]

Answer:

oh it's easy

Explanation:

Take the hydrate

N

a

2

S

2

O

3

∙

5

H

2

O

. Are there ionic forces between the

N

a

+

and the

S

2

O

2

−

3

and ion-dipole forces between the cation/anions and the water?

3 0
2 years ago
Find the volume of the rock in the images by the amount of water that it displaces
lyudmila [28]
The volume of the rock is 150
8 0
2 years ago
The range in size of most atomic radii is approximately what?
Nastasia [14]
It is approximately 10 ^ -10
3 0
3 years ago
when 45 grams of copper (ii) carbonate are decomposed with heat how many grams of carbon dioxide will be produced
Maksim231197 [3]

Answer:

16.02 g

Explanation:

the balanced equation for the decomposition of CuCO₃ is as follows

CuCO₃ --> CuO + CO₂

molar ratio of CuCO₃ to CO₂ is 1:1

number of CuCO₃ moles decomposed - 45 g / 123.5 g/mol = 0.364 mol

according to the molar ratio

1 mol of CuCO₃ decomposes to form 1 mol of CO₂

therefore 0.364 mol of  CuCO₃ decomposes to form 0.364 mol of CO₂

number of CO₂ moles produced - 0.364 mol

therefore mass of CO₂ produced - 0.364 mol x 44 g/mol = 16.02 g

16.02 g of CO₂ produced

8 0
3 years ago
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