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4 years ago

Look at the picture............................

Mathematics

1 answer:

Lemur [1.5K]4 years ago

7 0

There was $135 in Roland's bank account after the two-month period.

Step-by-step explanation:

Step 1:

Roland out $180 in his account at the beginning of July. This reduced by 25% over the next two months.

We need to determine how much 25% of $180 is. To do so we convert 25% into a fraction and multiply with 180.

25% of $180 $=\frac{25}{100} (180)= 45.$

So an amount of $45 reduced over two months.

Step 2:

To calculate the money Roland has in his account after two months, we subtract the amount reduced from the amount of money in his account at the beginning of July.

The amount of money in his bank account after the two-month period $180-45= 135.$

So there was $135 in Roland's bank account after the two-month period.

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Multiply or divide change your answer to a mixed frqction in lowest terms if necessary.

Alinara [238K]

24 divided by 8 equals 3
12 divided by 3 is 4
3 times 7 is 21
2 times 6 is 12
5 times 6 is 35
16 divided 4 is 4

6 0

3 years ago

Read 2 more answers

Find the area of the parallelogram with vertices:________.

marin [14]

Answer:

97.98

Step-by-step explanation:

The area of the parallelogram PQR is the magnitude of the cross product of any two adjacent sides. Using PQ and PS as the adjacent sides;

Area of the parallelogram = |PQ×PS|

PQ = Q-P and PS = S-P

Given P(0,0,0), Q(4,-5,3), R(4,-7,1), S(8,-12,4)

PQ = (4,-5,3) - (0,0,0)

PQ = (4,-5,3)

Also, PS = S-P

PS = (8,-12,4)-(0,0,0)

PS = (8,-12,4)

Taking the cross product of both vectors i.e PQ×PS

(4,5,-3)×(8,-12,4)

PQ×PS = (20-36)i - (16-(-24))j + (-48-40)k

PQ×PS = -16i - 40j -88k

|PQ×PS| = √(-16)²+(-40)²+(-88)²

|PQ×PS| = √256+1600+7744

|PQ×PS| = √9600

|PQ×PS| ≈ 97.98

Hence the area of the parallelogram is 97.98

3 0

4 years ago

2x + 3y = 15 and x - 3y = 3 What's the ordered pair

Ganezh [65]

Answer:

x = 6

y = 1

Step-by-step explanation:

to solve this system of equation we say let

2x + 3y = 15 .......................... equation 1

x - 3y = 3.................................. equation 2

from equation 2

x - 3y = 3.................................. equation 2

x = 3 + 3y.................................... equation3

substitute for x in equation 1

2x + 3y = 15 .......................... equation 1

2(3+3y) + 3y = 15

6 + 6y + 3y = 15

9y = 15 -6 ................................... combining the like terms

9y = 9

divide both sides by the coefficient of y

9y/9 = 9/9

y =1

put y = 1 in equation 3

x = 3 + 3y.................................... equation3

x = 3 + 3(1)

x = 3 +3

x = 6

therefore the value of x is 6 and y is 1 respectively

4 0

4 years ago

(04.05 LC)

Komok [63]

correct answer is option d.

Step-by-step explanation:

Here, we have The following expression to check Which of the following is a polynomial with roots: −square root of 3 , square root of 3, and 2 :

a. x3 + 3x2 − 5x − 15

For $-\sqrt{3}$ , $x^{3} + 3x^{2} -5x -15$ ⇒ $(-\sqrt{3}) ^{3} + 3(-\sqrt{3} )^{2} -5(-\sqrt{3} ) -15$ $\neq 0$ . So, this isn't the one. We move on further!

b. x3 + 2x2 − 3x − 6

For $-\sqrt{3}$ , $x^{3} + 2x^{2} -3x -6$ ⇒ $(-\sqrt{3}) ^{3} + 2(-\sqrt{3} )^{2} -3(-\sqrt{3} ) -6$ = 0 .

For $\sqrt{3}$ , $x^{3} + 2x^{2} -3x -6$ ⇒ $(\sqrt{3}) ^{3} + 2(\sqrt{3} )^{2} -3(\sqrt{3} ) -6$ = 0.

For 2 , $x^{3} + 2x^{2} -3x -6$ ⇒ $(2) ^{3} + 2(2)^{2} -3(2 ) -6$ $\neq 0$ . So, this isn't the one. We move on further!

c. x3 − 3x2 − 5x + 15

For $-\sqrt{3}$ , $x^{3}- 3x^{2} -5x -15$ ⇒ $(-\sqrt{3}) ^{3}- 3(-\sqrt{3} )^{2} -5(-\sqrt{3} ) -15$ $\neq 0$ . So, this isn't the one. We move on further!

d. x3 − 2x2 − 3x + 6

For $-\sqrt{3}$ , $x^{3} - 2x^{2} -3x +6$ ⇒ $(-\sqrt{3}) ^{3} - 2(-\sqrt{3} )^{2} -3(-\sqrt{3} ) +6$ = 0 .

For $\sqrt{3}$ , $x^{3} - 2x^{2} -3x +6$ ⇒ $(\sqrt{3}) ^{3} -2(\sqrt{3} )^{2} -3(\sqrt{3} ) +6$ = 0.

For 2 , $x^{3} - 2x^{2} -3x +6$ ⇒ $(2) ^{3} - 2(2)^{2} -3(2 ) +6$ = 0.

Therefore, correct answer is option d.

6 0

3 years ago

Operating on the triangle. using a straightedge, draw a random triangle. now carefully cut it out. next amputate the angles by s

S_A_V [24]

The sum of the measures of the angles in a triangle is always 180 degrees.

If you follow the procedure in the question, you will have a straight angle when you put the pieces together. All straight angles have 180 degrees. Therefore, there are 180 degrees in every triangle.

3 0

4 years ago